rotational kinetic energy of it's particles
Answer:
n = 4.35 x 10¹⁹
Explanation:
Given that
Voltage V= 12 V
Power rating of headlights = 41.8 W
We know that headlights of the car is connected in parallel connection.
We know that
Power = Current x Voltage
P = V I

I=3.48 A
Therefore the total current will be
I'= 3.48 + 3.48 A
I = 6.96 A
We know that
Charge = Current x time
q= I' t
q= 6.96 x 1
q= 6.96 C
The charge on electron ,e= 1.6 x 10⁻¹⁹
q= n e
n=Number of electron


n = 4.35 x 10¹⁹
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.
The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.
v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s
Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.
The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.
Combining this together we get:
(1) vx=40m/s and vy=10m/s
Answer:
(a) 0.345 T
(b) 0.389 T
Solution:
As per the question:
Hall emf, 
Magnetic Field, B = 0.10 T
Hall emf, 
Now,
Drift velocity, 

Now, the expression for the electric field is given by:
(1)
And

Thus eqn (1) becomes
where
d = distance
(2)
(a) When 

(b) When 
