Mention two adaptations of endo parasites.

1 answer:

4 0

The two adaptations of endo parasites:

Endoparasites (a parasite that lives in the internal organs or tissues of its host) produce some compounds of anti-enzymes which defuse or inactivate the host's digestive enzymes.
Endoparasites maintain their osmotic concentration equivalent to or significantly lower than the host cell for easy absorption of host water and nutrients.

There are three main classes of parasites involve:

Protozoa include Plasmodium, the single-celled organism. A protozoa inside the host can only replicate, or split.
Helminths parasites are worms.
Ectoparasites: These are living on, not in their hosts.

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Answer:

0.062 moles of hydrogen gas

Explanation:

We must first out down the reaction equation before we can attempt to solve the problem.

Mg(s) + 2HCl(aq) ----> MgCl2(aq) + H2(g)

Next we obtain the number of moles in 1.5 g of magnesium metal from;

Molar mass of magnesium = 24.3 gmol-1

Number of moles of magnesium= mass/molar mass = 1.5g/24.3gmol-1 = 0.062 moles

From the reaction equation;

1 mole of magnesium metal yields 1 mole of hydrogen gas

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Therefore, reaction of 1.5g of magnesium metal with excess hydrochloric acid will yield 0.062 moles of hydrogen gas.

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