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ryzh [129]
2 years ago
7

Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1

.0m/s and vy=3.0m/svy=3.0m/s and that at time t2=2.5st2=2.5s the components are vx=4.0m/svx=4.0m/s and vy=3.0m/svy=3.0m/s . Find (a) the components of average acceleration and (b) the magnitude and direction of the average acceleration during this interval.
Physics
1 answer:
Nonamiya [84]2 years ago
7 0

Answer:

a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

Magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}

Explanation:

t_1=2\ \text{s}

v_x=1\ \text{m/s}

v_y=3\ \text{m/s}

t_2=2.5\ \text{s}

v_x=4\ \text{m/s}

v_y=3\ \text{m/s}

Average acceleration in the different axes

a_x=\dfrac{\Delta v_x}{\Delta t}\\\Rightarrow a_x=\dfrac{4-1}{2.5-2}\\\Rightarrow a_x=6\ \text{m/s}^2

a_y=\dfrac{\Delta v_y}{\Delta t}\\\Rightarrow a_y=\dfrac{3-3}{2.5-2}\\\Rightarrow a_y=0\ \text{m/s}^2

The components of the acceleration is a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

The magnitude of acceleration

a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2

Direction

\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}

The magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}.

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A car with a mass of 710 kg is traveling at 37 km/hr. It accelerates to a speed of 120 km/hr in 12.6 seconds. What is the net fo
guajiro [1.7K]

Answer: The net force acting on the car 1,299.3 N.

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