<u>Answer:</u> The volume of the gas is 178.76 L
<u>Explanation:</u>
The ideal gas equation is given as:
.......(1)
where
P = pressure of the gas = 675 torr
V = volume of gas = ?
n = number of moles of gas = 6.45 moles
R = Gas constant = 62.36 L.torr/mol.K
T = temperature of the gas = ![27^oC=[27+273]K=300K](https://tex.z-dn.net/?f=27%5EoC%3D%5B27%2B273%5DK%3D300K)
Putting values in equation 1, we get:
Hence, the volume of the gas is 178.76 L
Explanation:
P1V1 = P2V2
(100.7 kPa)(0.75 L) = (99.8 kPa)V2
V2 = (100.7 kPa)(0.75 L)/(99.8 kPa)
= 0.757 L
Answer: F. Endothermic…………………
<span>Answer:
(16.2 g C2H6O2) / (62.0678 g C2H6O2/mol) / (0.0982 kg) = 3.9704 mol/kg = 3.9704 m
a.)
(3.9704 m) x (1.86 °C/m) = 7.38 °C change
0.00°C - 7.38 °C = - 7.38 °C
b.)
(3.9704 m) x (0.512 °C/m) = 2.03 °C change
100.00°C + 2.03 °C = 102.03 °C</span>
I searched it up on Google and I got 473.176 Hope this helps.
