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inna [77]
4 years ago
15

Whats heptane's formula?

Chemistry
1 answer:
Dovator [93]4 years ago
5 0
Heptane means seven carbon atoms and since the general formula is CnH2n+2, heptane will be C7H16
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Guys help me out please ​
kifflom [539]

Answer:

See explanation

Explanation:

A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions(Khan Academy).

From the species shown in the image we can write the molecular equation, ionic equation and net ionic equation and also identify the spectator ions.

Chemical equation: KX + BY --------> BX + AY

Ionic Equation; X^- + A^+ + B^+ + Y^- -----> BX + A^+ + Y^-

Spectator ions;  A^+ and Y^-

Net Ionic Equation; X^- + B^+ ------> BX

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3 years ago
Which characteristic can be inherited?
FinnZ [79.3K]

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long toes

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What is the temperature in degrees Celsius on the thermometer below?​
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8 0
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Read 2 more answers
What is the vapor pressure of a liquid at 305.03 K if its ∆Hvap = 28.9 kJ/mol and its normal boiling point is 341.88 K?
ASHA 777 [7]

<u>Answer:</u> The vapor pressure of the liquid is 0.293 atm

<u>Explanation:</u>

To calculate the vapor pressure of the liquid, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm

P_2 = pressure of the liquid = ?

\Delta H_{vap} = Heat of vaporization = 28.9 kJ/mol = 28900 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 341.88 K

T_2 = final temperature = 305.03 K

Putting values in above equation, we get:

\ln(\frac{P_2}{1})=\frac{28900J/mol}{8.314J/mol.K}[\frac{1}{341.88}-\frac{1}{305.03}]\\\\\ln P_2=-1.228atm\\\\P_2=e^{-1.228}=0.293atm

Hence, the vapor pressure of the liquid is 0.293 atm

5 0
3 years ago
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