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Dmitry [639]
3 years ago
9

Two obiect accumulated a charge of

Physics
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

q_1=4.5\mu C=4.5\cdot 10^{-6}C is the magnitude of the 1st charge

q_2=2.8\mu C=2.8\cdot 10^{-6}C is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N

So, the closest answer is

A) 181.24 N

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Two resistors, of R1 = 3.11 Ω and R2 = 6.15 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna
Firlakuza [10]
Part (a):
1- Since the resistors are in series, therefore, the total resistance is the summation of the two resistors.
Therefore:
Rtotal = R1 + R2 = 3.11 + 6.15 = 9.26 ohm

2- Since the two resistors are in series, therefore, the current flowing in both is the same. We will use ohm's law to get the current as follows:
V = I*R
V is the voltage of the battery = 24 v
I is the current we want to get
R is the total resistance = 9.26 ohm
Therefore:
24 = 9.26*I
I = 24 / 9.26
I = 2.59 ampere

Part (b):
To get the voltage across the second resistor, we will again use Ohm's law as follows:
V = I*R
V is the voltage we want to get
I is the current in the second resistor = 2.59 ampere
R is the value of the second resistor = 6.15 ohm
Therefore:
V = I*R
V = 2.59 * 6.15
V = 15.9285 volts

Hope this helps :)
7 0
3 years ago
If there no motion then there is no force acting? true or false
goblinko [34]

Answer:

false.

Explanation:

If a object is at rest it does not means that no force is acting on the object.

There can be a scenario that all to forces acting on the object balance each other and the net force required for motion is zero.

So, the given statement is false.

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3 years ago
What is an example of 'Centre of Gravity'?
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Water bottle and a paper towel role
5 0
3 years ago
What mass of electrons would be required to just neutralize the charge of 4.8 g of protons?
suter [353]
Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of q=1.6 \cdot 10^{-19} C, and a mass of m_p = 1.67 \cdot 10^{-27}kg. So, the number of protons is
N_p =  \frac{M}{m_p}= \frac{0.0048 kg}{1.67 \cdot 10^{-27}kg}=2.87 \cdot 10^{24} And so the total charge of these protons is Q_p = qN_p = (1.6 \cdot 10^{-19}C)(2.87 \cdot 10^{24})=4.6\cdot 10^5 C

So, the neutralize this charge, we must have N_e electrons such that their total charge is
Q_e = -4.6 \cdot 10^5 C
Since the charge of each electron is q_e = -1.6 \cdot 10^{-19}C, the number of electrons needed is
N_e =  \frac{Q_e}{q}= \frac{-4.6 \cdot 10^5 C}{-1.6 \cdot 10^{-19}C}=2.87 \cdot 10^{24}
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is m_e=9.1 \cdot 10^{-31}kg, the total mass of electrons should be
M_e = N_e m_e = (2.87 \cdot 10^{24})(9.1 \cdot 10^{-31}kg)=2.6 \cdot 10^{-6}kg
6 0
3 years ago
Do any individual air molecules travel the length of the tube? how do you know?
Ivanshal [37]

When a gas is inside the tube, the individual air molecules travel the length of the tube.

<h3>What is molecules?</h3>

The individual particle of a gas element moving randomly inside the element structure.

When the gas contained in a container, the molecules move randomly inside it. According to the kinetic theory of gases, molecules travel the mean distance. The air molecules vibrates horizontally parallel to the length of the tube.

In an open tube, air molecules are distant from each other. So, they can travel the length of the tube.

Thus, individual air molecules travel the length of the tube.

Learn more about molecules.

brainly.com/question/19922822

#SPJ4

7 0
2 years ago
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