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4 years ago

In which orbitals would the valence electrons for selenium (Se) be placed?

Chemistry

1 answer:

igor_vitrenko [27]4 years ago

7 0

Answer:

s orbital and p orbital

Explanation:

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Which of the following is the correctly balanced equation for the reaction of a Ca(OH)2 and HNO3

lakkis [162]

Your answer is
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O I hope it is at least :P

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3 years ago

What word is used to refer to a group of organ systems working together?

kotegsom [21]

Answer:

Explanation:

in my opinion,The answer would be organism

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6 0

3 years ago

The energy in eV for light with a wavelength of 6250 angstroms is _. Note - there are 1.6 x 10-12 erg in 1 eV.

vivado [14]

Answer:

2 eV

Explanation:

The energy of a photon of light is given by the formula

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

In this problem we have:

$h=6.63\cdot 10^{-34} Js$

$c=3.0\cdot 10^8 m/s$

$\lambda=6250 A = 6250\cdot 10^{-10} m$ is the wavelength of the photon

Therefore, the energy in Joules is

$E=\frac{(6.63\cdot 10^{-34})(3.0\cdot 10^8)}{6250\cdot 10^{-10}}=3.2\cdot 10^{-19}J$

We want to convert this energy into electronvolts: we know that the conversion factor is

$1 eV = 1.6\cdot 10^{-19}J$

Therefore,

$E=\frac{3.2\cdot 10^{-19}}{1.6\cdot 10^{-19}}=2 eV$

5 0

3 years ago

An actual measurement of a sample is 3.5 m. The measured

strojnjashka [21]

Answer: b 29 percent

Explanation:

5 0

3 years ago

Read 2 more answers

A piece of glass has a temperature of 83˚C. Liquid that has a temperature of 43˚C is poured over the glass, completely covering

Lerok [7]

Answer: The specific heat of the liquid is $2520J/kg^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

.................(1)

where,

q = heat absorbed or released

= mass of glass = x kg

= mass of liquid = x kg

= final temperature =

$T_1$ = temperature of glass = $83^oC$

$T_2$ = temperature of liquid = $43^oC$

$c_1$ = specific heat of glass = $840J/kg^0C$

$c_2$ = specific heat of liquid= ?

Now put all the given values in equation (1), we get

$-[(x\times 840\times (53-83)]=x\times c_2\times (53-43)$

$c_2=2520J/kg^0C$

Therefore, the specific heat of the liquid is $2520J/kg^0C$

5 0

3 years ago