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velikii [3]
3 years ago
11

In a combustion analysis, the carbon in a hydrocarbon fuel is

Chemistry
1 answer:
scoray [572]3 years ago
7 0
During a combustion reaction the carbon in a hydrocarbon compound is paired with Oxygen (O2) in the air to form Carbon-Dioxide (CO2), whilst the Hydrogen too pairs with Oxygen to form water vapour (H2O). Heat is also produced during this reaction.
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Why is pseudo science not considered real science
swat32

Pseudo-science is not considered real science because it is not testable.

Answer:  Option A

<u>Explanation:</u>

Pseudoscience primarily includes beliefs, theories or practices that are somehow incompatible with the scientific facts. The pseudoscience can’t be tested on the basis of science.

Let’s take an example of astrology. Some people believe that stars and other celestial bodies draw a significant impact on their life i.e. Good or bad thing it's just because their stars are working either in a positive or negative manner.

But, this belief doesn’t have any well-proved or authentic background over which the whole concept can rely on. Hence, pseudoscience is not taken as a real science as a lack of strong proves.

8 0
3 years ago
Balance the equation 2kclo3 3o2 + kcl
sergij07 [2.7K]
Answer is 2KClO3 3O2 + 2KCl
5 0
3 years ago
The formula equation of Acetylene + oxygen ----&gt; carbon dioxide + water ​
snow_lady [41]

Answer:

The final balanced equation is : 2C2H2+5O2→4CO2+2H2O.

8 0
2 years ago
If you were given two transparent liquids how would you determine which is pure and which is salt water
Tpy6a [65]
Based off the salt levels in each water.
8 0
2 years ago
weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the
valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 751 mm Hg

P_2 = final pressure of gas = 495 mm Hg

V_1 = initial volume of gas = 340 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 30^oC=273+30=303K

T_2 = final temperature of gas = -27^oC=273-27=246K

Now put all the given values in the above equation, we get:

\frac{751\times 340}{303}=\frac{495\times V_2}{246}

V_2=419L

Thus the volume of the balloon at this altitude is 419 L

8 0
2 years ago
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