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user100 [1]
3 years ago
13

Describe three ways that individuals can combat global warming.

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
8 0
They could stop driving cars and opt in for walking or riding a bike, drive an electric car because they don't take gas. They could also get their electricity from renewable resources such as electricity from wind mills and solar panels and hydro-electric.
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How many carbon atoms are present in 0.46 moles of C2H6O?
solmaris [256]
Here, Number of atoms = 0.46 * 6.23 * 10^23   [ Avogadro's number ]
= 2.77 * 10^23 

In short, Your Answer would be Option B

Hope this helps!
4 0
4 years ago
A 150-lb person burns about 2700 Calories to run a marathon. How much energy is burned in kJ?
Alex17521 [72]
The question above is simply asking us to convert the value from calories into kilojoules. Therefore, we need some factor to multiply to be able to convert it to such units. For calories to kJ, the factor would be 4.184.

2700 cal ( 4.184 kJ/cal) = 11296.8 kJ
5 0
3 years ago
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What is 0.000345 expressed in scientific notation?
Viktor [21]
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3 years ago
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A _______ is a repeating disturbance or vibration that transfers or moves energy from place to place without transporting mass.
Harlamova29_29 [7]
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The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
garri49 [273]

Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater (m_{sw}), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

m_{sw} = \rho_{sw}\cdot V_{sw}

Where:

\rho_{sw} - Density of seawater, measured in grams per liters.

V_{sw} - Volume of seawater, measured in liters.

If V_{sw} = 1.5\times 10^{21}\,L and \rho_{sw} = 1030\,\frac{g}{L}, then:

m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)

m_{sw} = 1.545\times 10^{24}\,g

The total mass of sodium chloride is determined by the following ratio:

r = \frac{m_{NaCl}}{m_{sw}}

m_{NaCl} = r\cdot m_{sw}

Given that m_{sw} = 1.545\times 10^{24}\,g and r = 0.035, the total mass of sodium chloride in all the seawater in the world is:

m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)

m_{NaCl} = 5.408\times 10^{22}\,g

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

8 0
4 years ago
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