Question

How many moles are in 1.2x10^3 grams of ammonia(NH3) ?

Answer 1

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = $1.2\times 10^3g$

Molar mass of ammonia = 17.031 g/mole

Formula used :

$\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}$

$\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles$

Therefore, the number of moles present in ammonia is, 70.459 moles.

Answer 2

Molar mass NH3 = 17.031 g/mol

1 mole NH3 ---------- 17.031 g
?? moles -------------- 1.2x10³ g

moles NH3 =  1 x ( 1.2x10³  ) / 17.031

moles NH3 = 1.2x10³ / 17.031

= 70.45 moles of NH3

hope this helps!