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Alexxx [7]
3 years ago
6

How many moles are in 1.2x10^3 grams of ammonia(NH3) ?

Chemistry
2 answers:
miskamm [114]3 years ago
5 0

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = 1.2\times 10^3g

Molar mass of ammonia = 17.031 g/mole

Formula used :

\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}

\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles

Therefore, the number of moles present in ammonia is, 70.459 moles.

olga nikolaevna [1]3 years ago
4 0
Molar mass NH3 = 17.031 g/mol

1 mole NH3 ---------- 17.031 g
?? moles -------------- 1.2x10³ g

moles NH3 =  1 x ( 1.2x10³  ) / 17.031

moles NH3 = 1.2x10³ / 17.031

= 70.45 moles of NH3

hope this helps!
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