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Assoli18 [71]
3 years ago
10

The acceleration due to gravity is g at the earth's surface. an earth satellite is orbiting at a distance from the earth's surfa

ce equal to one earth radius. at this location, what is the acceleration due to gravity
Physics
1 answer:
disa [49]3 years ago
6 0

The acceleration due to gravity is g/4

The acceleration above the earth surface is given by the relation

g^'=gr^2/〖(h+r)〗^2

Since the satellite orbits the earth in a orbit of radius equal to earth radius, therefore

g^'=(gr^2)/〖(r+r)〗^2 =g/4

Thus the acceleration due to gravity on the satellite is g/4.

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;

2 2 25.1 rad s

T 0.250

 

   

(a)

 

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(b)

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2 2 25.1 rad s

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 

   

(a)

 

2 2

k m    0.200 kg 25.1 rad s 126 N m

(b)

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2

2 2 2.00 0.178 m

Explanation:

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3 years ago
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3 years ago
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