All categories

2 years ago

....................

Physics

2 answers:

Irina18 [472]2 years ago

6 0

Answer:

-28.01m/s is your answer

muminat2 years ago

3 0

Answer:

-28.014 is the answer

You might be interested in

Which of the following best describes alternating current? current that increases and decreases in temperature current that cons

VARVARA [1.3K]

Current in which charge changes direction

7 0

3 years ago

Read 2 more answers

Find what is the ratio of the internal energy of hydrogen UB. To the internal energy of helium UJ for two moles of hydrogen and

finlep [7]

Answer:

Ration of internal energy of hydrogen to the internal energy of helium is equal to $\frac{5}{6}$

Explanation:

As we know

degree of freedom of hydrogen is 5

Degree of freedom of helium is 3

Internal energy of hydrogen

$\frac{5}{2} * 2 * RT = 5 *RT$

Internal energy of helium

$\frac{3}{2} * 4 * RT = 6 *RT$

Ration of internal energy of hydrogen to the internal energy of helium is equal to $\frac{5}{6}$

4 0

3 years ago

Explain how geothermal energy and tidal energy can be used effectively?

Vadim26 [7]

Geothermal energy can heat, cool, and generate electricity: Geothermal energy can be used in different ways depending on the resource and technology chosen—heating and cooling buildings through geothermal heat pumps, generating electricity through geothermal power plants, and heating structures through direct-use applications.

Tidal can be harnessed in three different ways; tidal streams, barrages, and lagoons.

3 0

2 years ago

Read 2 more answers

When a 360 nF air capacitor is connected to a power supply, the energy stored in the capacitor is 1.85 x 10-5 J. While the capac

GaryK [48]

Answer:

(a) Approximately $10.1\; {\rm V}$ .

Explanation:

Let $C$ denote the capacitance of a capacitor. Let $V$ be the potential difference (voltage) between the two plates of this capacitor. The energy $E$ stored in this capacitor would be:

$\displaystyle E = \frac{1}{2}\, C\, (V^{2})$ .

Rearrange this equation to find an expression for the potential difference $V$ in terms of capacitance $C$ and energy $E$ :

$\begin{aligned}V^{2} &= \frac{2\, E}{C} \end{aligned}$ .

$\begin{aligned}V &= \sqrt{\frac{2\, E}{C}} \end{aligned}$

The capacitance $C$ of this capacitor is given in nanofarads. Convert that unit to standard unit (farads):

$\begin{aligned}C &= 360\; {\rm nF} \\ &= 360\; {\rm nF} \times \frac{1\; {\rm F}}{10^{9}\; {\rm nF}} \\ &= 3.60 \times 10^{-7}\; {\rm F}\end{aligned}$ .

Given that the energy stored in this capacitor is $E = 1.85 \times 10^{-5}\; {\rm J}$ , the potential difference across the capacitor plates would be:

$\begin{aligned}V &= \sqrt{\frac{2 \times 1.85 \times 10^{-5}\; {\rm J}}{3.60 \times 10^{-7}\; {\rm F}}} \\ &\approx 10.1\; {\rm V}\end{aligned}$ .

7 0

2 years ago

Power=170 watts time=20 seconds

Art [367]

The answer is w=p.t. Substitution:hz 110.20.

4 0

3 years ago

.................... ​

....................