The correct answer to the question is :
EXPLANATION :
As per the question, the specific heat of gold is given as c =
The heat given to the gold dQ = 195 J
The mass of the gold is given as m = 15 gram.
We are asked to calculate the change in temperature.
Let the change in temperature is dT.
We know that dQ = mcdT
[ANS]
Hence, the change in temperature is 100 degree celsius.
The correct answer is:
the distance of the orbiting object to Earth.
In fact, we know that the gravitational force that keeps the object in circular motion around the Earth is equal to the centripetal force, so we can write:
If we re-arrange the equation, we find an expression for the tangential speed of the object:
and we see that it depends on 3 quantities: G, M (the mass of the Earth) and r (the distance of the object from the Earth).
Answer:
a) Time period is 3.3 seconds
b) The frequency is 0.3030 Hz
c) amplitude is 0.25 m
d) maximum speed is 0.476 m/s
Explanation:
Given the data in the question;
a) Period
Time Period T = Time taken for one oscillation
T = 33s / 10 = 3.3 seconds
Therefore, Time period is 3.3 seconds
b) Frequency
we know that frequency is the inverse of time period
so;
Frequency f = 1/T = 1 / 3.3 s
Frequency f = 0.3030 Hz
Therefore, The frequency is 0.3030 Hz
c) amplitude
amplitude A = ( 60 cm - 10 cm )
A = × 50 cm
A = 25 cm
A = 0.25 m
Therefore, amplitude is 0.25 m
d) maximum speed of the glider
maximum speed = ωA
and ω = 2π/T
so maximum speed =
A
so we substitute
so maximum speed =
× 0.25 m
so maximum speed = 0.476 m/s
Therefore, maximum speed is 0.476 m/s
Answer:
The distance from the radio station is 0.28 light years away.
Solution:
As per the question:
Distance, d = 4 ly
Frequency of the radio station, f = 854 kHz =
Power, P = 50 kW =
Now,
From the relation:
P = nhf
where
n = no. of photons/second
h = Planck's constant
f = frequency
Now,
Area of the sphere, A =
Now,
Suppose the distance from the radio station be 'r' from where the intensity of the photon is
Now,
We know that:
1 ly =
Thus