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LUCKY_DIMON [66]
3 years ago
8

Help please,thank you (question 20)

Mathematics
1 answer:
bixtya [17]3 years ago
3 0

There are four properties involving multiplication that will help make problems easier to solve. They are the commutative, associative, multiplicative identity and distributive properties. Multiplicative Identity Property: The product of any number and one is that number. For example 5 * 1 = 5.

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What’s 3•5+-5•4 <br><br> And the dot is multiplication!
NeTakaya
-5 is the answer ...............

8 0
3 years ago
Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circ
RSB [31]

Answer:

146°

Step-by-step explanation:

Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circle. Given m arch AB=64° and ⦣ABC=73°, m ⦣ABC=__ ° and m arch AC=__ °.

Solution:

Given that:

arc AB = 64° and ⦣ABC=73°

The Central Angle Theorem states that the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points. The inscribed angle is any point along the outer arc AB and the two points A and B.

Therefore arc AC is the central angle of ⦣ABC. Using the central angle theorem gives:

arc AC = 2 * ⦣ABC

substituting:

arc AC = 2 * 73

arc AC = 146°

8 0
2 years ago
427,266 to the nearest ten thousand
GaryK [48]

Answer:

430,000

Step-by-step explanation:

Since the thousandths place is more than 4 you can round up the ten thousands

7 0
2 years ago
Read 2 more answers
Solve . (5 points) Question 5 options: 1) −20 2) −24 3) 20 4) 24
e-lub [12.9K]

Answer:

18 21 24 24 =87 maybe trying to help

8 0
2 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
2 years ago
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