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3 years ago

Help please,thank you (question 20)

Mathematics

1 answer:

bixtya [17]3 years ago

3 0

There are four properties involving multiplication that will help make problems easier to solve. They are the commutative, associative, multiplicative identity and distributive properties. Multiplicative Identity Property: The product of any number and one is that number. For example 5 * 1 = 5.

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Paula and Chad each ate 2/5 of a batch of cookies. Together, what fraction of the batch of cookies did they eat?

masha68 [24]

$\bf \stackrel{Paula}{\cfrac{2}{5}}+\stackrel{Chad}{\cfrac{2}{5}}\implies \cfrac{2+2}{5}\implies \cfrac{4}{5}$

8 0

3 years ago

Pleaseeeee answer ASAP ✌

Gre4nikov [31]

Answer:

h=10

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

In an airplane 35% of the passengers are children they’re 140 children on the airplane how many passengers are on the airplane

Angelina_Jolie [31]

Answer:

there are 49 passengers

Step-by-step explanation: 35%=0.35

0.35*140= 49

3 0

2 years ago

Find the value of $x$ for the right triangle. A right triangle with base labeled x and hypotenuse labeled 12 units. Angle betwee

slamgirl [31]

Answer:

6 feets

Step-by-step explanation:

The triangle described in the question has been sketched in the picture attached below :

From the triangle, we could solve for X, which is the base of the triangle using trigonometry :

Sinθ = opposite / hypotenus

Sin 30° = x / 12

0.5 = x / 12

x = 12 * 0.5

x = 6 feets

Hence base, x = 6 feets

8 0

3 years ago

A recent survey by the cancer society has shown that the probability that someone is a smoker is P(S)=0.29. They have also deter

GuDViN [60]

<u>Answer:</u>

The correct answer option is P (S∩LC) = 0.16.

<u>Step-by-step explanation:</u>

It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.

So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).

P (LC|S) = P (S∩LC) / P (S)

Substituting the given values to get:

0.552 = P(S∩LC) / 0.29

P (S∩LC) = 0.552 × 0.29 = 0.16

5 0

3 years ago