Answer:
? can u explain. Not sure what ur asking
Explanation:
Answer:
Reactions, 2, 3 and 5 make precipitates
Explanation:
1. The halogens always make aqueous salts with elements from group 1
2. Phosphate anion can make insoluble salts, the same as carbonate.
3. Nitrate anion always make aqueous salts
4. Sulfate anion makes aqueous salts except with Ag⁺, Pb⁺² and group 2
1. KI(aq) + NaCl(aq) → KCl(aq) + NaI(aq)
2. 2Na₃PO₄ (aq) + 3CoCl₂(aq) → 6NaCl(aq) + Co₃(PO₄)₂(s) ↓
3. Na₂CO₃ (aq) + CuCl₂ (aq) → 2NaCl (aq) + CuCO₃ (s) ↓
4. 2LiNO₃ (aq) + Na₂SO₄ (aq) → Li₂SO₄ (aq) + 2NaNO₃(aq)
5. CrCl₂ (aq) + Li₂CO₃ (aq) → 2LiCl (aq) + Cr₂(CO₃)₂ (s) ↓
I think the answer would be d
The ball isn't magnetic, therefore, the nail wasn't attracted towards the ball, but rather towards the magnet.
Answer:
The water ligands surrounding the cobalt metal center are being replaced by ethylenediamine and chloride ligands which results in a different crystal field splitting. Thus, the energy associated with electron transitions between the do-orbitals will differ for the two compounds showing a color change.
Explanation:
The five d-orbitals are usually degenerate. Upon approach of a ligand, the d-orbitals split into two sets of orbitals depending in the nature of the crystal field.
The magnitude of crystal field splitting is affected by the nature of the ligand. Ligands having filled p-π orbitals such as ethylenediamine lead to greater crystal field splitting.
The change in the colour that takes place when ethylenediamine is added to the solution of cobalt(II) chloride occurs due to a different crystal field splitting pattern. Thus, the energy associated with electron transitions between the d-orbitals now differ for the two compounds showing a color change.
