Answer:
50 m/s opposite direction to the motion of the truck
Explanation:
From the question,
Applying the law of conservation of momentum
mu+m'u' = V(m+m')...….. Equation 1
Where m = mass of the truck, u = initial velocity of the truck, m' = mass of the car, u' = initial velocity of the car, V = Final velocity after collision
Given: m = 2500 kg, u = 20 m/s, m' = 1000 kg, V = 0 m/s (both car stop after collision)
Substitute these values into equation 1
2500(20)+1000(u') = 0(2500+1000)
2500(20)+1000(u') = 0
Solve for u'
u' = -[2500(20)]/1000
u' = -50 m/s
The negative sign shows that the car travels in opposite direction to the truck
Hence the car initial velocity before collision is 50 m/s in opposite direction to the motion of the truck
Answer:
Explanation:
PE = mgh = 2.0(9.8)(1.2) = 23.52 ≈ 24 J
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s...center of mass
KE = ½mv² = ½(45)(1800/600)² = 202.5 ≈ 203 J
Answer:
F_total = 29.4 N, directed to the right of particle 2
Explanation:
We must solve this problem in parts, first we calculate each force and then we apply Newton's law to add the forces.
Let's use Coulomb's law to calculate each force
F = 
particles 1 and 2
q₁ = 8.0 10⁻⁶ C, q₂ = 3.5 10⁻⁶ C x₁₂ = 0.10 m
F₁₂ = 9 10⁹ 8.0 3.5 10⁻¹² / 0.1²
F₁₂ = 2.59 10¹ N
Since the two charges are of the same sign, this force is repulsive and is directed towards the positive side of the x axis.
particles 2 and 3
q₂ = 3.6 10⁻⁶ C, q₃ = 2.5 10⁻⁶ C, x₂₃ = 0.15 m
we calculate
F₂₃ = 9 10⁹ 3.5 2.5 10⁻¹²/ 0.15²
F₂₃ = 3.5 N
as the charge is of different sign, the force is attractive, therefore it is directed to the right of the load 2
Now we add the forces as vectors
F_total = ∑ F = F₁₂ + F₂₃
F_total = 25.2 +3.5
F_total = 29.4 N
directed to the right of particle 2
Answer:
zzyibgsdwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwe
Explanation:
Electromagnetic force between the molecules!