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Crazy boy [7]
3 years ago
14

A boy picks up a bowling ball. Which of the following choices correctly describes the interaction between the boy and the bowlin

g ball? A. The boy exerts an upward force on the ball, and the bowling ball exerts a downward force on the boy. B. Both forces are equal in strength. The boy exerts an upward force on the bowling ball, and the bowling ball exerts a downward force on the boy. C. The bowling ball’s force on the boy is the greater force. The boy exerts an upward force on the bowling ball because the ball accelerates. D. The bowling ball does not exert a force on the boy because the boy does not accelerate. E. The boy exerts an upward force on the bowling ball, and the bowling ball exerts a downward force on the boy. F. The boy’s force on the bowling ball is the greater force.
Physics
2 answers:
irakobra [83]3 years ago
8 0

A, E, and F are all true.

(A and E say the same thing.)

F explains why the ball accelerates upward.

Hatshy [7]3 years ago
5 0

Answer: F

Explanation: The boy is controlling the bowling ball therefore he can use greater force

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a truck of mass 2 500 kg travelling at the speed of 20 ms–1 to the right collide head-on with another car of mass 1 000 kg. If b
monitta

Answer:

50 m/s opposite direction to the motion of the truck

Explanation:

From the question,

Applying the law of conservation of momentum

mu+m'u' = V(m+m')...….. Equation 1

Where m = mass of the truck, u = initial velocity of the truck, m' = mass of the car, u' = initial velocity of the car, V = Final velocity after collision

Given: m = 2500 kg, u = 20 m/s, m' = 1000 kg, V = 0 m/s (both car stop after collision)

Substitute these values into equation 1

2500(20)+1000(u') = 0(2500+1000)

2500(20)+1000(u') = 0

Solve for u'

u' = -[2500(20)]/1000

u' = -50 m/s

The negative sign shows that the car travels in opposite direction to the truck

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3 years ago
Someone please help me! And I will mark you as brainlist!!
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Answer:

Explanation:

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2 years ago
Particles q1 = +8.0 UC, 92 = +3.5 uc, and
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Answer:

   F_total = 29.4 N,    directed to the right of particle 2

Explanation:

We must solve this problem in parts, first we calculate each force and then we apply Newton's law to add the forces.

Let's use Coulomb's law to calculate each force

         F = k \frac{q_1q_2}{r_{12}^2}

particles 1 and 2

q₁ = 8.0 10⁻⁶ C, q₂ = 3.5 10⁻⁶ C x₁₂ = 0.10 m

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Since the two charges are of the same sign, this force is repulsive and is directed towards the positive side of the x axis.

particles 2 and 3

q₂ = 3.6 10⁻⁶ C, q₃ = 2.5 10⁻⁶ C, x₂₃ = 0.15 m

we calculate

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as the charge is of different sign, the force is attractive, therefore it is directed to the right of the load 2

Now we add the forces as vectors

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