<u>Answer:</u>
<em>The number of moles of HCl actually present is 0.000988</em>
<u>Explanation:</u>
<em>The balanced chemical equation of the given reaction is </em>
Here one mole of HCl reacts with one mole of NaOH to form one mole of NaCl and one mole of water. Here the molarity of HCl is given as 0.026M.
<em>molarity of NaOH is 0.032M
</em>
molarity is the number of moles per unit volume of solution.
we have to calculate the number of moles in 36 mL of HCl.
<em>38 mL=36/1000=0.038L
</em>
<em>the number of moles in 38 mL of HCl is given by
</em>
<em>no of moles =
</em>
Answer:
c turns back when iodine is added result indicated a chemical reaction
Answer:
false
Explanation:
I'm pretty sure it's compared to carbon
<span>Answer is: 2940 mL of
the HCL solution.</span>
c₁(HCl) = 10.0 M.
V₂(AgNO₃<span>) = ?.
c</span>₂(AgNO₃<span>) = 0.85 M.
V</span>₁(AgNO₃<span>) = 250 mL </span>÷ 1000 mL/L = 0.25 L.
<span>
c</span>₁<span> - original concentration of the solution, before it
gets diluted.
c</span>₂<span> - final concentration of the solution, after dilution.
V</span>₁<span> - volume to be diluted.
V</span>₂<span> - final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂<span>.
V</span>₂(HCl) = c₁ · V₁ ÷ c₂.
<span>
V</span>₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.
<span>
V</span>₂(HCl) = 2.94 L ·
1000 mL = 2940 mL.
