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BARSIC [14]
3 years ago
12

If you had 6H2 molecules and 4O2 molecules, how many H2O molecules could you produce?

Chemistry
1 answer:
ZanzabumX [31]3 years ago
7 0

Answer:

6

Explanation:

As , 2H2 + O2 = 2H2O

with 6 H2, 4O2 is excess.

H2O molecules formed = 6

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Hydrogen and oxygen atoms react to form water by __________ electrons.
DedPeter [7]
D
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Formation of water is a covalent bond which involves the sharing of electrons between two reacting atoms so that both can attain the stable octet structure
4 0
2 years ago
What type of reaction occurs without the addition of heat?
maria [59]

The type of reaction that occurs without the addition of heat is called spontaneous reaction. That is option D.

<h3>What is spontaneous reaction?</h3>

Spontaneous reaction is defined as the reaction where by new substances are formed naturally without the addition of extra energy in the form of heat.

Therefore, the type of reaction that occurs without the addition of heat is called spontaneous reaction

Learn more about heat here:

brainly.com/question/13439286

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5 0
2 years ago
At STP, fluorine is a gas and iodine is a solid. This observation can be explained by the fact that fluorine has
motikmotik
<span>The answer is 4. The molecules of each material entice each other over dispersion (London) intermolecular forces. Whether a substance is a solid, liquid, or gas hinge on the stability between the kinetic energies of the molecules and their intermolecular magnetisms. In fluorine, the electrons are firmly apprehended to the nuclei. The electrons have slight accidental to stroll to one side of the molecule, so the London dispersion powers are comparatively weak. As we go from fluorine to iodine, the electrons are far from the nuclei so the electron exhausts can more effortlessly misrepresent. The London dispersion forces developed to be increasingly stronger.</span>
6 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
What type of compound is fe3n2
Shkiper50 [21]

Fe3N2, also known as Iron (II) nitride, is an ionic compound.


Ionic compounds are compounds that consists of metals and non-metals bonded with ionic bonds. The metal ion gives up electron(s) to the non-metals.


Since iron is a metal and nitrogen is an non-metal, the bond they would form would be an ionic bond. Iron gives up 2 electrons to form iron(II) ion, while nitrogen gains 3 electrons to form nitride ion. Since one iron cannot let a nitrogen gain 3 electrons, so in the compound, there would be 3 iron (ii) ions that has given up 6 electrons in total while 2 nitride ions have gained 6 electrons in total.

8 0
2 years ago
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