Question

An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in the tire.
What is the new pressure of the tire after the temperature change?
? atm

Answer 1

Answer:

2.65 atm.

Explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

• If n and V are constant, and have different values of P and T:

(P₁T₂) = (P₂T₁).

P₁ = 3.0 atm, T₁ = 30°C + 273 = 303 K,

P₂ = ??? atm, ​T₂ = -5°C + 273 = 268 K.

∴ P₂ = (P₁T₂)/(T₁) = (3.0 atm)(268 K)/(303 K) = 2.65 atm.