Ask question

Ask question

All categories

3 years ago

9

A 1.3 kgkg block slides along a frictionless surface at 1.3 m/sm/s . A second block, sliding at a faster 5.0 m/sm/s , collides w

ith the first from behind and sticks to it. The final velocity of the combined blocks is 2.5 m/sm/s . What was the mass of the second block?

2 answers:

weqwewe [10]3 years ago

3 0

Answer:

0.624 kg

Explanation:

We are given that

Mass of one block, $m_1=1.3 kg$

$v_1=1.3 m/s$

$v_2=5 m/s$

$V=2.5 m/s$

We have to find the mass of second block.

Mass of second block, $m_2=\frac{m_1V-m_1v_1}{v_2-V}$

Substitute the values

$m_2=\frac{1.3\times 2.5-1.3\times 1.3}{5-2.5}$

$m_2=0.624 kg$

Hence, the mass of second block=0.624Kg

krok68 [10]3 years ago

3 0

Answer:

The mass of the second block is 0.624 kg.

Explanation:

Given that,

Mass of the block 1, m₁ = 1.3 kg

Speed of block 1, u₁ = 1.3 m/s

Speed of block 2, u₂ = 5 m/s

The final velocity of the combined blocks is 2.5 m/s, V = 2.5 m/s

It is a case of inelastic collision. Using the conservation of linear momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)V\\\\1.3\times 1.3+5m_2=(1.3+m_2)2.5\\\\1.69+5m_2=3.25+2.5m_2\\\\m_2=0.624\ kg$

So, the mass of the second block is 0.624 kg.

You might be interested in

Need answers quick !! will give brainliest !!

stiv31 [10]

Answer:

use the bowl of water because Earth's magnetic field is relatively weak. Allowing it to float freely on the water, allows the magnetized needle to freely react to Earth's magnetic field, causing it to align North to South. If you watched closely, the same end of the needle should always point to the North

Explanation:

6 0

2 years ago

Calculate the recoil speed of a 1.4 kg rifle shooting 0.006 kg bullets with muzzle speed of 800 m/a.3.43 m/s

Angelina_Jolie [31]

Answer:

a) 3.43 m/s

Explanation:

Due to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.

The total momentum before the bullet is shot is zero, because they are both at rest, so:

$p_i = 0$

Instead the total momentum of the system after the shot is:

$p_f = mv+MV$

where:

m = 0.006 kg is the mass of the bullet

M = 1.4 kg is the mass of the rifle

v = 800 m/s is the velocity of the bullet

V is the recoil velocity of the rifle

The total momentum is conserved, therefore we can write:

$p_i = p_f$

Which means:

$0=mv+MV$

Solving for V, we can find the recoil velocity of the rifle:

$V=-\frac{mv}{M}=-\frac{(0.006)(800)}{1.4}=-3.43 m/s$

where the negative sign indicates that the velocity is opposite to direction of the bullet: so the recoil speed is

a) 3.43 m/s

5 0

3 years ago

Carbon dioxide in the blood is removed from the body through the A. kidneys B. lungs C. mouth D. skin

natka813 [3]

Answer:

<h2>C) Mouth</h2>

Explanation:

<h2>When we inhale air, it contains oxygen. The lungs take in oxygen and the heart and the other body parts use it.</h2><h2>Carbon dioxide is removed from the blood mouth when we exhale.</h2>

8 0

2 years ago

The focal length of david's lens is 60 cm. if rebecca stands in front of david at a distance of do and david perceives the posit

Makovka662 [10]

if rebecca stands in front of david at a distance of do and david perceives the position of rebecca at di, di will be +84 cm

<h3>What is focal length ?</h3>

How strongly light converges or diverges depends on an optical system's focal length, which is the inverse of optical power. A system with a positive focus length is said to converge light, whereas one with a negative focal length is said to diverge light.

focal length = +60 cm

magnification m = -0.40

focal length being positive an magnification negative.

given lens is a convex lens.

for a lens

m = di/do and 1/f = (1/di) - (1/do)di

= -0.4do1/f = (1/-0.4do) - 1/do do

= -210 cmdi = -0.4 * -210

di = +84 cm

To learn more about focal length go to - brainly.com/question/25779311

#SPJ4

5 0

2 years ago

En la Tierra un volcán puede expulsar rocas verticalmente hasta una altura máxima H. A) ¿A qué altura (en términos de H) llegarí

Nonamiya [84]

A) 2.64 H

The maximum height that the expelled rock can reach can be found by using the equation:

$v^2-u^2 = 2gd$

where

v = 0 is the velocity at the maximum height

u is the initial velocity

g is the acceleration of gravity

d is the maximum height

Solving for d,

$d=\frac{-u^2}{2g}$

We see that the maximum heigth is inversely proportional to g. On the Earth,

$d=H$ and $g=g_e = -9.81 m/s^2$

So we can write:

$\frac{H}{H'}=\frac{g_m}{g_e}$

where H' is the maximum height reached on Mars, and $g_m = -3.71 m/s^2$ is the acceleration of gravity on Mars. Solving for H',

$H' = \frac{g_e}{g_m}H = \frac{-9.81}{3.71}H=2.64 H$

B) 2.64T

The time after which the rock reaches the maximum height can be found by using

$v=u+gt$

where

v = 0 is the velocity at the maximum height

u is the initial velocity

Solving for t,

$t=\frac{v-u}{g}$

The total time of the motion is twice this value, so:

$t=2\frac{v-u}{g}$

So we see that it is inversely proportional to g.

On the Earth, t = T. So we can write:

$\frac{T}{T'}=\frac{g_m}{g_E}$

where T' is the total time of the motion on Mars. Solving for T',

$T' = \frac{g_e}{g_m}T=\frac{-9.81}{-3.71}T=2.64T$

4 0

3 years ago