A 1.3 kgkg block slides along a frictionless surface at 1.3 m/sm/s . A second block, sliding at a faster 5.0 m/sm/s , collides w
2 answers:
Answer:
0.624 kg
Explanation:
We are given that
Mass of one block,
We have to find the mass of second block.
Mass of second block,
Substitute the values
Hence, the mass of second block=0.624Kg
Answer:
The mass of the second block is 0.624 kg.
Explanation:
Given that,
Mass of the block 1, m₁ = 1.3 kg
Speed of block 1, u₁ = 1.3 m/s
Speed of block 2, u₂ = 5 m/s
The final velocity of the combined blocks is 2.5 m/s, V = 2.5 m/s
It is a case of inelastic collision. Using the conservation of linear momentum as :
So, the mass of the second block is 0.624 kg.
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Explanation:
It is given that,
Velocity of the particle moving in straight line is :
We need to find the distance (x) traveled by the particle during the first t seconds. It is given by :
Using by parts integration, we get the value of x as :
Hence, this is the required solution.
Torque can cause the angular momentum vector to rotate in UCM. This motion is called _Conservation of Angular momentum__________.
Answer:
Conservation of Angular momentum
Explanation:
The motion of an object in a circular path at constant speed is known as uniform circular motion (UCM). An object in UCM is constantly changing direction, and since velocity is a vector and has direction, you could say that an object undergoing UCM has a constantly changing velocity, even if its speed remains constant.
The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.
Key Points
When an object is spinning in a closed system and no external torques are applied to it, it will have no change in angular momentum.
The conservation of angular momentum explains the angular acceleration of an ice skater as she brings her arms and legs close to the vertical axis of rotation.
If the net torque is zero, then angular momentum is constant or conserved.
Angular Momentum
The conserved quantity we are investigating is called angular momentum. The symbol for angular momentum is the letter L. Just as linear momentum is conserved when there is no net external forces, angular momentum is constant or conserved when the net torque is zero. We can see this by considering Newton’s 2nd law for rotational motion:
τ→=dL→dt, where
τ is the torque. For the situation in which the net torque is zero,
dL→dt=0.
If the change in angular momentum ΔL is zero, then the angular momentum is constant; therefore,
⇒
L =constant
L=constant (when net τ=0).
This is an expression for the law of conservation of angular momentum.
Example and Implications
An example of conservation of angular momentum is seen in an ice skater executing a spin, The net torque on her is very close to zero,
because (1) there is relatively little friction between her skates and the ice, and (2) the friction is exerted very close to the pivot point.
Conservation of angular momentum is one of the key conservation laws in physics, along with the conservation laws for energy and (linear) momentum. These laws are applicable even in microscopic domains where quantum mechanics governs; they exist due to inherent symmetries present in nature.
Answer:
6.0 × W/
Explanation:
From Wien's displacement formula;
Q = e A
Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.
The emissive intensity = = e
Given from the question that: e = 0.6 and T = 1000K, thus;
emissive intensity = 0.6 ×
= 0.6 × 1.0 ×
= 6.0 ×
Therefore, the emissive intensity coming out of the surface is 6.0 × W/
.