Taking into account the animals and the landscape being mentioned, we can confirm that the combination of these forms<u><em> part of an </em></u><u><em>ecosystem</em></u><u><em>.</em></u>
An ecosystem is described as an area consisting of:
- Plants
- Animals
- Bacteria
- Weather
- Landscape
and many other factors, which all work together to form a small pocket of life.
Ecosystems are described as containing both living and non-living elements, meaning biotic and non-biotic parts. A community or population, on the other hand, <u>are used to consider only the </u><u>biotic </u><u>or </u><u>living factors </u><u>of an </u><u>ecosystem</u><u>. </u>Therefore, since the question includes the rock bottom (a<em><u> non-biotic factor</u></em>) as a part of the makeup, the only correct grouping is that of an ecosystem.
To learn more visit:
brainly.com/question/13952438?referrer=searchResults
Answer:
15 mol Mg
Explanation:
Step 1: Find conversions
Avagadro's Number: 6.022 × 10²³
Step 2: Use Dimensional Analysis
= 14.6179 mol Mg
Step 3: Simplify
We have 2 sig figs.
14.6179 mol Mg ≈ 15 mol Mg
<span>1 mol of N2 is 28 gms, thus, 2.93mol is 84 gms.
According to the equation-
N (2 + 3H (2) = 2NH(3)
28gms (1mol) of N2 produces 34gms of NH3
so, 84gms of N2 will produce:
28gms of N2----->34gms of NH3
84gms of N2-----> 28/84 = 34 / x
x= (34*84) / 28
Answer: 102gms</span>
Fe 3+ + SCN- --> FeSCN 2+
<span>.......Fe 3+ .......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>
<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>so, using your Keq, there would be no SCN- or Fe 3+ left.....all would be in the form of FeSCN 2+</span>
Answer:
Answer is: mass of copper is 127 grams.
Balanced chemical reaction: Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s).
m(Ag) = 432 g.
n(Ag) = m(Ag) ÷ M(Ag).
n(Ag) = 432 g ÷ 108 g/mol.
n(Ag) = 4 mol.
From chemical reaction: n(Ag) : n(Cu) = 2 : 1.
n(Cu) = 4 mol ÷ 2 = 2 mol.
m(Cu) = n(Cu) · M(Cu).
m(Cu) = 2 mol · 63.5 g/mol.
m(Cu) = 127 g
Explanation:
