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Snowcat [4.5K]
3 years ago
14

Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is _______ , and the chem

ical formula of the compound is __ __ __ __.

Chemistry
2 answers:
Kisachek [45]3 years ago
7 0

Answer:

Hello my Friend! The answer is: Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is +3 , and the chemical formula of the compound is Mn2O3.

Explanation:

Manganese can have two oxidation states: +2 and +3, but in this case, the "(III)"  indicates that in this compound, the state of oxidation is +3.

zhannawk [14.2K]3 years ago
5 0

Explanation:

Manganese(III) oxide is a chemical compound with chemical formula Mn_{2}O_{3}.

Since, manganese is a transition metal so, in order to attain stability it will lose valence electrons and as oxygen is chemically combining with it will take up the electrons.

Hence, it will lead to the formation of an ionic compound. Therefore, oxidation state of Mn in this compound is +3 and oxidation state of oxygen is -2.

Therefore, we can conclude that Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is +3, and the chemical formula of the compound is Mn_{2}O_{3}.

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The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

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2/248 = V2/273

273 × 2 = 248V2

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V2 = 546/248

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Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L

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