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Snowcat [4.5K]
3 years ago
14

Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is _______ , and the chem

ical formula of the compound is __ __ __ __.

Chemistry
2 answers:
Kisachek [45]3 years ago
7 0

Answer:

Hello my Friend! The answer is: Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is +3 , and the chemical formula of the compound is Mn2O3.

Explanation:

Manganese can have two oxidation states: +2 and +3, but in this case, the "(III)"  indicates that in this compound, the state of oxidation is +3.

zhannawk [14.2K]3 years ago
5 0

Explanation:

Manganese(III) oxide is a chemical compound with chemical formula Mn_{2}O_{3}.

Since, manganese is a transition metal so, in order to attain stability it will lose valence electrons and as oxygen is chemically combining with it will take up the electrons.

Hence, it will lead to the formation of an ionic compound. Therefore, oxidation state of Mn in this compound is +3 and oxidation state of oxygen is -2.

Therefore, we can conclude that Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is +3, and the chemical formula of the compound is Mn_{2}O_{3}.

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What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
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Answer:

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

if in         184 g (1 mole) of MgBr₂ we have 160 g of Br⁻

then in   4.867 g of MgBr₂ we have Y g of Br⁻

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4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

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