Answer:
X= -Y + 2/2 Y=-X + 3/2
Explanation:
I don't know how to simplify it anymore. You would get x=-y+3/2 and y=-x+3/2
Answer:
The attractive force is negative and MgO has a higher melting point
Explanation:
From Couloumb's law:
Energy of interaction, E = k 
where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.
If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).
In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten
The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.
Hence the compound MgO would have a higher melting point than NaF.
Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
- Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
- units of volume are mL, liter, cm³ or m³.
Given,
in this question, volume occupied by gas at 10.9⁰c is 733cm³.
we have to find out temperature at which gas occupies volume of 950 cm³.
First, convert temperature from celcius to Kelvin
10.9⁰c = 10.9 + 273.15 = 284.05 K
By equation or Boyle's Law
P1 x V1 / T1 = P2 x V2 / T2
Pressure is constant here
therefore, V1 / T1 = V2 / T2
here, V1 = 733 cm³
T1 = 284.05 K
V2 = 950 cm³
we have to find out T2
So, 733 / 284.05 = 950 / T2
T2 = 284.05 × 950 / 733 = 368.14 K
= 94. 99⁰c
Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
Learn more about Boyle's Law here:
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Answer: 1.348 ×10^23 atoms
Explanation:
Given that volume = 1.00L
At standard condition, the volume of a gas is 22.4L/mol (at S.T.P)
Volume = mole /volume at STP
1 = mole/22.4
Mole= 22.4mol.
Also
Mole = number of atoms /Avogradro constant
Where avogrado's constant = 6.02×10²³
22.4 = number of atoms/6.02×10²³
Number of atoms = 1.348×10^25atoms