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Rzqust [24]
3 years ago
15

An atom (not a hydrogen atom) absorbs a photon whose associated wavelength is 300 nm and then immediately emits photon whose ass

ociated wavelength is 640 nm. How much net energy is absorbed by the atom in this process?
Chemistry
1 answer:
KIM [24]3 years ago
6 0

Answer:

The net energy is 2.196 eV

Explanation:

Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.

Using:

ΔE = h*c*(1/λ_{1} - 1/λ_{2})

where:

ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602*10^{-19} J.

h = 4.135*10^{-15} eVs

c = 3*10^{8} m/s

λ_{1} = 300 nm = 300*10^{-9} m

λ_{2} = 640 nm = 640*10^{-9} m

Thus:

ΔE = 4.135*10^{-15} eVs*3*10^{8} m/s*(\frac{1}{300*10^{-9}m } }-\frac{1}{640*10^{-9}m })

ΔE = 4.135*10^{-15}*3*10^{8}*1.77*10^{6} eV = 2.196 eV

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Answer:

X= -Y + 2/2     Y=-X + 3/2

Explanation:

I don't know how to simplify it anymore. You would get x=-y+3/2 and y=-x+3/2

4 0
3 years ago
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The faster the object is moving the more portential energy it has?
Mazyrski [523]

Answer:

sure

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8 0
3 years ago
1. Calculate the attractive bonding force for NaF and for MgO when the ions just touch. Based on the attractive bonding force, w
Andreas93 [3]

Answer:

The attractive force is negative and MgO has a higher melting point

Explanation:

From Couloumb's law:

Energy of interaction, E = k \frac{q1q2}{r}

where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.

If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).

In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten

The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.

Hence the compound MgO would have a higher melting point than NaF.

5 0
3 years ago
Is gas occupies 733 cm at 10.9 at what temp will it occupy 950 cm
alexgriva [62]

Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.

  • Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
  • units of volume are mL, liter, cm³ or m³.

Given,

in this question, volume occupied by gas at 10.9⁰c is 733cm³.

we have to find out temperature at which gas occupies volume of 950 cm³.

First, convert temperature from celcius to Kelvin

10.9⁰c = 10.9 + 273.15 = 284.05 K

By equation or Boyle's Law

P1 x V1 / T1 = P2 x V2 / T2

Pressure is constant here

therefore, V1 / T1 = V2 / T2

here, V1 = 733 cm³

T1 = 284.05 K

V2 = 950 cm³

we have to find out T2

So, 733 / 284.05 = 950 / T2

T2 = 284.05 × 950 / 733 = 368.14 K

= 94. 99⁰c

Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.

Learn more about Boyle's Law here:

https://brainly.in/question/2900894

#SPJ9

5 0
2 years ago
Gaseous neon has a density of 0.900 g/L at standard conditions. How many neon atoms are in 1.00 L of neon gas at standard condit
Anvisha [2.4K]

Answer: 1.348 ×10^23 atoms

Explanation:

Given that volume = 1.00L

At standard condition, the volume of a gas is 22.4L/mol (at S.T.P)

Volume = mole /volume at STP

1 = mole/22.4

Mole= 22.4mol.

Also

Mole = number of atoms /Avogradro constant

Where avogrado's constant = 6.02×10²³

22.4 = number of atoms/6.02×10²³

Number of atoms = 1.348×10^25atoms

3 0
3 years ago
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