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sp2606 [1]
3 years ago
9

A 1.50-kilogram ball is attached to the end of a 0.520-meter string and swung in a circle. The velocity of the ball is 9.78 m/s.

What is the tension in the string?
Chemistry
1 answer:
Sedaia [141]3 years ago
7 0

Answer:

F centripetal force (tension) = 275.9  N

Explanation:

Given data:

Mass = 1.50 kg

Radius = 0.520 m

Velocity of ball = 9.78 m/s

Tension = ?

Solution:

F centripetal force (tension) =  m.v² / R

F centripetal force (tension) = 1.50 kg . (9.78 m/s)² / 0.520 m

F centripetal force (tension) = 1.50 kg . 95.65 m²/s² / 0.520 m

F centripetal force (tension) = 143.5 kg. m²/s² / 0.520 m

F centripetal force (tension) = 275.9  N

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2 years ago
What is the total pressure exerted by a mixture of 48.0 grams of CH4 and 56.0 grams of
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The pressure of the gas is obtained as 48 atm.

<h3>What is the total pressure?</h3>

Now we know that;

Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles

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P = 31 * 0.082 * 286/15

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Learn more about pressure of a gas:brainly.com/question/18124975

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1 year ago
How to find the number of neutrons in an isotope?
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