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Nata [24]
2 years ago
10

How many moles of NaCl are there in 3.90 x 10^24 particles?

Chemistry
1 answer:
vagabundo [1.1K]2 years ago
5 0

Answer:

6.48 moles

Explanation:

One mole of a substance is equal to 6.022*10^23 particles which is called Avagadro's number.

6.022*10^23 = 1 mole

3.90*10^24 = x moles

x = (3.90*10^24*1) / (6.022*10^23) = 6.48 moles

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Which of the following is the electrical charge on an atom that contains 6 electrons, 3 neutrons, and 4 protons?
Y_Kistochka [10]

Answer:

Its electrical charge is -2.

4 0
3 years ago
Suppose a system returns to its original overall, internal energy ((∆U) after the following changes. In step 1, 25 J of work is
Brums [2.3K]

Answer:

Heat transfer in step 2 = 47.75 J

Explanation:

Internal energy = heat + work done

U = Q + W

In a cyclic process the total internal energy change of the system = 0.

In the process there are two steps. The total heat exchange in the process is the sum of heat exchanges in the two processes.

We have to find the heat exchange in step 2.

In step 1,

W = 1.25 J          Q = -37 J

U_{1} = -37 + 1.25 = -35.75 J

In step 2, the internal energy change will be negative of that in step 1.

U = 35.75 J

W = -12 J

U = Q + W

35.75 = Q -12

Q = 47.75 J

Heat transfer in step 2 = 47.75 J

6 0
3 years ago
What is the value for (delta)G at 1000 K if (delta)H = -220 kJ/mol and (delta)S = -0.05 kJ/(molK)?
tankabanditka [31]
The system is isothermal, so we use the formula:
(delta)G = (delta)H - T (delta) S

Plugging in the given values:
(delta)G = -220 kJ/ mol - (1000K) (-0.05 kJ/mol K)
(delta)G = -170 kJ/mol

If we take a basis of 1 mol, the answer is
D. -170 kJ 
6 0
3 years ago
Read 2 more answers
If the initial temperature of a movable cylinder was 50 degrees Celsius
slega [8]

Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

Final temperature (T₂) = 273 K

Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 273 k

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

5 0
3 years ago
Imagine snow on top of a mountain. Describe at least two ways energy could be transferred as the seasons change?
Mademuasel [1]

Answer:

at summer season the snow will melt and will produce water and using generators we can produce electric energy and in spring and winter can produce electric energy also using the wind

8 0
2 years ago
Read 2 more answers
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