Explanation:
Convert the time to seconds : 5minutes × 60 = 300seconds
Acceleration = Velocity / Time
Acceleration = 20m/s / 300s
Acceleration = 0.067m/s²
Distance = Velocity × Time
Distance = 20m/s × 300seconds
Distance = 6000m
On the half way down (object falling down with the initial speed = 0)
Answer:
v₀ₓ = 14.34 m / s
Explanation:
We can solve this problem using the projectile launch equations.
Let's look for the time it takes to descend to the height of the cave
y = t - ½ g t²
As it rises horizontally the initial vertical speed is zero
y = 0 - ½ gt²
t = √2 y / g
t = √2 7.3 / 9-8
t = 1.22 s
This is the same time to cross the ravine
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 17.5 / 1.22
v₀ₓ = 14.34 m / s
This is the minimum speed.
The distance between the two balls at the given force is 0.7 m.
The given parameters;
- <em>mass of each ball, m = 0.8 kg</em>
- <em>gravitational force between the balls from sample problem C, F = 8.92 x 10⁻¹¹ N</em>
The distance between the balls is calculated by applying Coulomb's law as shown below;
Thus, the distance between the two balls is 0.7 m.
Learn more about Coulomb's law here: brainly.com/question/14270204