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2 years ago

Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number.

Chemistry

2 answers:

Dovator [93]2 years ago

7 0

Answer:

-958 spontaneuos

Explanation:

kenny6666 [7]2 years ago

5 0

Answer:

-958

spontaneous

Explanation:

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What is the mass of 5 mole of ammonia . Calculate the number of NH₃ molecules, nitrogen atom and hydrogen atoms in it..

Aloiza [94]

Molar mass of NH_3

$\\ \sf\longmapsto 14u+3(1u)$

$\\ \sf\longmapsto 14u+3u$

$\\ \sf\longmapsto 17g/mol$

We know.

No of moles=Given mass/Molar mass

$\\ \sf\longmapsto Given\;Mass=17(5)$

$\\ \sf\longmapsto Given \:Mass\:of\:NH_3=85g$

Now

Lets write the balanced equation

$\\ \sf\longmapsto N_2+3H_2=2NH_3$

There is 2moles of Ammonia
3moles of H_2
1mole of N_2

Now

$\boxed{\sf No\:of\:Molecules =No\:of\;moles\times Avagadro\:no}$

For Hydrogen

$\\ \sf\longmapsto 3\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 18.069\times 10^{23}$

$\\ \sf\longmapsto 1.8\times 10^{22}molecules$

For Ammonia

$\\ \sf\longmapsto 2\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 12.046\times 10^{23}$

$\\ \sf\longmapsto 1.2\times 10^{22}molecules$

For Nitrogen

$\\ \sf\longmapsto 1\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 6.023\times 10^{23}molecules$

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2 years ago

Which of the following has the greatest mass?

Annette [7]

Answer:

I guess one mole. of mercury

Explanation:

because mercury is denser

8 0

2 years ago

In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of

BARSIC [14]

Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is tartaric acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL$

Putting values in above equation, we get:

$2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL$

$M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M$

0.0042 M is the molarity of tartaric acid in this sample of wine.

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3 years ago

Is solid sodium + liquid water to dissolved hydroxide + gaseous hydroxide a single replacement reaction

saul85 [17]

2Na + 2H20 ----> 2NaOH + H2

5 0

3 years ago

9.31x10<br> ? x 10<br> What’s the other number

miskamm [114]

Answer:

93.1

Explanation:

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2 years ago