The energy to be dissipated is proportional to 1/2 m v^2 ie proportional to v^2 for the same car
<span>In turn F * d = work done. </span>
<span>F is constant ( same brakes) </span>
<span>so d is proportional to v^2 </span>
<span>if v is multiplied by 3 then d is multiplied by 3^2 = 9 </span>
<span>distance = 180m</span>
Explanation:
u= 0 ( because car start rest)
v=400
t=3.5
v-u/t
400-0/3.5
400/3.5
114m/s
f= 12000
f=ma
12000=m*114
m=12000/114
105 kg approx
Answer:
Explanation:
In Coulomb's law the force between the charged objects depends on the distance between them which is inversely proportional to the force and the charge of the objects which is directly proportional to the force with proportional constant K.
Because q₂ is near to another charged object q₁, then, it will experience an electric force exerted by q₁.
F₁₂ = K |q₁| |q₂|/r²
= K (|-e|) (|+e|)/r²
= (9.0 x 10⁹ N.m²/C²) x (1.6 x 10⁻¹⁹ C) x (1.6 x 10⁻¹⁹ C)/ (0.80 x 10⁻⁹)²
= 3.6 x 10⁻¹⁰ N
Force F₁₂ = F₂₁
Because the two charged objects have different signs , then, the force between them will be an attractive force.