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pav-90 [236]
3 years ago
7

Solve this question with explanation Best answer will be brainliest 40 points given

Physics
2 answers:
Yuliya22 [10]3 years ago
7 0

Answer:

12 km/h

Explanation:

Average Speed = Distance / Time (or rate)

Pick a point on the graph for Ian and plug in values.

For example, 20 minutes -> 4km

Hence, Average speed = 4km ÷ 20 minutes = 0.2 km/min

0.2 km/min × 60 = 12 km/h

siniylev [52]3 years ago
5 0
Ian’s average speed seems to be about 5. It looks like for every kilometer it takes 5 minutes
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What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equ
Elena L [17]

Answer:

Maximum force will be equal to 720 N

Explanation:

We have given that spring constant k=1.2\times 10^4N/m

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by

F=kx=1.2\times 10^4\times 0.06=720N

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N

6 0
4 years ago
Why is rock away from ocean ridges older? Is it because if the rocks are away from cracks in the crust, there is no way for any
andreyandreev [35.5K]

Answer:

the rocks are away from cracks in the crust

Explanation:

   The new crust is pushed away from the Ocean Ridge in both directions as newer crust is formed. This is called sea floor spreading. The crust that makes up the sea floor starts to have time to accumulate a layer of sediments as it gets older and moves away from the Ocean Ridge.

6 0
2 years ago
Read 2 more answers
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Oduvanchick [21]
It's easy raising the barbell.
3 0
3 years ago
Light from an argon laser strikes a diffraction grating that has 4,917 lines per cm. The first-order principal maxima are separa
miss Akunina [59]

Answer:

Wavelength is 4.8x10^-7m

Explanation:

See attached file

3 0
3 years ago
1. A car with an initial velocity of 5m/s acceaccelerates uniformly at 3 metre per second square until it reaches a velocity of
alisha [4.7K]

Explanation:

here, u = 5m/s,a = 3m/s2, v = 23m/s, t = ?, s = ?

v = u+at

23 = 5 + 3t

t = 23- 5/3 = 18/3 = 6 sec

s= ut + 1/2 at ^2

s = 5 * 6 + 1/2 * 3 * (6)^2

s = 30 + 1/2 * 3 * 36

s = 30 + 18 * 3

s= 30 + 54 = 84 m

here, u = 0, a = x, t = 5min = 300 sec, s= 5.8km = 5800m

s = ut + 1/2 at^2

5800 = 0 * 300 + 1/2 * x * (300)^2

5800 = 1/2 * x * 90000

5800= 45000 x

x = 5800/45000

x = 0.12m/sec^2

here, v = 0, t = 6sec, s = ?, a = - 9.8m/s2

s = UT + 1/2 at ^2

s = 29.4 * 3 + 1/2 * - 9.8 * (3)^2

s= 88.2 - 44.1

s= 44.1 m

s = ut + 1/2 at ^2

s = 0 * 1 + 1*2 * 9.8 * (1)^2

s = 4.9m

hope it helps you

8 0
3 years ago
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