Scott-Dannemiller, Koeninger, Briscoe, and Carter
Christopher-Briscoe, Dannemiller, and Koeninger
Dianne-Koeninger, Briscoe, and Carter
Kailee-Koeninger and Carter
The block with the bullet lodged in the block is now travelling at 2.133 m/s.
<h3>What is momentum conservation principle?</h3>
When there is no external force acting on the system, the momentum remains conserved.
For inelastic collision, after collision both objects travel with common speed.
m1u1 + m2u2 =(m1 +m2)v
Substitute initial velocity of bullet u1 =320 m/s , initial velocity of block u2 =0, mass of bullet m1 = 0.1 kg and mass of block m2 = 14.9 kg.
Solve for the final velocity of bullet,
0.1 x 320 + 14.9 x 0 = (0.1 +14.9) x v
v = 2.133 m/s
Thus, the block with the bullet lodged in block now travelling at 2.133 m/s.
Learn more about momentum conservation principle.
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