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dedylja [7]
3 years ago
12

I need help on question 5

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0
Weathering, erosion, impact, pressure  
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A thin flake of mica (n=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the wiew
Llana [10]

To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

Where

L = Thickness

n = Index of refraction of each material

\lambda = Wavelength

Our values are given as

\Phi = 7(2\pi)

L=t

n_1 = 1.58

n_2 = 1

\lambda = 550nm

Replacing our values at the previous equation we have

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))

t = \frac{7*550}{1.58-1}

t = 6637.931nm \approx 6.64\mu m

Therefore the thickness of the mica is 6.64μm

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