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drek231 [11]
3 years ago
5

A rocket's acceleration is 6.0 m/s2. Assuming it starts at 0 m/s, how long will it take for the rocket to reach a velocity of 42

m/s?
250 s
0.14s
7.0 s
290 s
Physics
1 answer:
Over [174]3 years ago
4 0
There are few equations that link acceleration and velocity.

One of them is derived from the definition of acceleration - is the rate of change of velocity in respect with time

a = v-u/t
at=v-u

a = acceleration
v=velocity at the end
u=velocity at the start
t=time

Now put everything you know and solve for time.

6t = 42 -0
6t = 42
t = 42 / 6
t = 7 second

It takes 7 seconds for the roccet to reach a velocity of 42 m/s

Hope it helps :).

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A carpenter lifts a 10-kg piece of wood to his shoulder 1.5 m above the ground. He then sets the wood on his truck at 1.0 m abov
FinnZ [79.3K]

Answer:

<em>500Joules</em>

Explanation:

Kinetic energy = 1/2mv²

m is the mass of the wood

v is the velocity

Given

Mass = 10kg

Velocity v = 10m/s

Substitute into the formula and get KE

KE = 1/2 * 10 * 10²

KE  = 1/2 * 1000

KE = 500Joules

<em>Hence the kinetic energy of the wood during delivery is 500Joules</em>

8 0
3 years ago
A circular coil of radius r = 5 cm and resistance R = 0.2 is placed in a uniform magnetic field perpendicular to the plane of th
Yuri [45]

Answer:

the question is incomplete, the complete question is

"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"

2.6mA

Explanation:

we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.

using the formula be low,

E=-\frac{d}{dt}(BACOS\alpha )\\

where B is the magnitude of the field and A is the area of the circular coil.

First, let determine the area using \pi r^{2} \\ where r is the radius of 5cm or 0.05m

A=\pi *(0.05)^{2}\\ A=0.00785m^{2}\\

since we no that the angle is at 0^{0}

we determine the magnitude of the magnetic filed

B=0.5e^{-t} \\t=2s

E=-(0.5e^{-2} * 0.00785)

E=-0.000532v\\

the Magnitude of the voltage is 0.000532V

Next we determine the current using ohm's law

V=IR\\R=0.2\\I=\frac{0.000532}{0.2} \\I=0.0026A

I=2.6mA

6 0
4 years ago
What are the three types of protists? When is an organism classified as a protist?
borishaifa [10]

Answer:

Protozoa, Algae and Fungus-like protists.  And by how they obtain nutrition.

Explanation:

7 0
4 years ago
What is the “cosmic haystack problem”? List as many of its components as you can think of.
shepuryov [24]

Answer:

About the universe, The problem isn't just that the sky has billions of stars to search but there are also billions of frequencies.

8 0
3 years ago
An electron in orbit around a (one proton) nucleus has a speed of about 106 m/s. Deduce the equivalent current due to the motion
dedylja [7]

Answer:

(a) -4.8\times 10^{-4}A (B) 4.22\times 106{-24}A/m^2

Explanation:

We have given the the speed of the electron =10^6 m/sec

The time period of the electron is given by T=\frac{2\pi r}{v} where r is the Bohr radius, which is equal to 5.29\times 10^{-11}m

So time period T=\frac{2\times \pi \times 5.29\times 10^{-11}}{10^6}=3.324\times 10^{-16}m/sec

(A) We know that current i=\frac{q}{T}=\frac{-e}{T}=\frac{-1.6\times 10^{-19}}{3.324\times 10^{-16}}=-4.8\times 10^{-4}A

(B) Magnetic moment is given by \mu =IA , where I is current and A is area

So \mu =IA=-4.8\times 10^{-4}\times 3.14\times (5.29\times 10^{-11})^2=4.22\times 10^{-24}A/m^2

3 0
3 years ago
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