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evablogger [386]
3 years ago
10

SOMEONE PLEASE HELP WITH 7,8&9

Chemistry
1 answer:
professor190 [17]3 years ago
8 0
7.) 3
8.) i think it's 2
9.) 3
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Consider the following reaction where Kc = 154 at 298 K.2NO(g) + Br2(g) 2NOBr(g)A reaction mixture was found to contain 4.64×10-
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Answer:

The reaction is not at equilibrium and reaction must run in forward direction.

Explanation:

At the given interval, concentration of NO = \frac{4.64\times 10^{-2}}{1}M=4.64\times 10^{-2}M

Concentration of Br_{2} = \frac{4.56\times 10^{-2}}{1}M=4.56\times 10^{-2}M

Concentration of NOBr = \frac{0.102}{1}M=0.102M

Reaction quotient,Q_{c} , for this reaction = \frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}

species inside third bracket represents concentrations at the given interval.

So, Q_{c}=\frac{(0.102)^{2}}{(4.64\times 10^{-2})^{2}\times (4.56\times 10^{-2})}=106

So, the reaction is not at equilibrium.

As Q_{c}< K_{c} therefore reaction must run in forward direction to increase Q_{c} and make it equal to K_{c}.

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