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Andrews [41]
3 years ago
8

Two ladybugs sit on a rotating disk that is slowing down at a constant rate. The ladybugs are at rest with respect to the surfac

e of the disk and do not slip. Ladybug 1 is halfway between ladybug 2 and the axis of rotation. How does the rotational speed of ladybug 1 compare to ladybug 2?
Physics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

The two ladybugs have same rotational (angular) speed

Explanation:

The rotational (angular) speed of an object in circular motion is defined as:

\omega=\frac{\theta}{t}

where

\theta is the angular displacement

t is the time interval considered

Here we have two ladybugs, which are located at two different distances from the axis. In particular, ladybug 1 is halfway between ladybug 2 and the axis of rotation. However, since they rotate together with the disk, and the disk is a rigid body, every point of the disk cover the same angle \theta in the same time t: this means that every point along the disk has the same angular speed, and therefore the two ladybugs also have the same angular speed.

On the other hand, the linear speed of the two ladybugs is different, because it follows the equation:

v=\omega r

where r is the distance from the axis: and since the two ladybugs are located at different r, they have different linear speed.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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Which one of the following statements concerning superconductors is false? A constant current can be maintained in a superconduc
julsineya [31]

Answer:

All materials are superconducting at temperatures near absolute zero kelvin.

Explanation:

All materials are superconducting at temperatures near absolute zero kelvin is false concerning superconductors.

8 0
3 years ago
A parallel-plate capacitor has a plate area of 0.2 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magni
barxatty [35]

Answer:

The potential difference across the plates is 226 V.

Explanation:

Given;

area of the capacitor plate, A = 0.2 m²

separation, d = 0.1 mm = 0.1 x 10⁻³ m

charge on each plate, Q = 4 x 10⁻⁶ C

Charge on the capacitor is given by;

Q = CV

Where;

C is the capacitance of the capacitor, given as;

C = ε₀A / d

Then, the potential difference across the plates is given by;

V = \frac{Q}{C} = \frac{Qd}{\epsilon_o A} = \frac{(4*10^{-6})(0.1*10^{-3})}{(8.85*10^{-12})(0.2)}\\\\V = 226 \ V

Therefore, the potential difference across the plates is 226 V.

5 0
2 years ago
A grey hound can run about 40/mph is it velocity,acceleration, or speed
loris [4]

Answer: Speed

Explanation:

Speed is the time it takes something to travel a certain distance. Accelaration is the rate at which an object's speed changes. Velocity is a vector of the object's speed and direction.

5 0
3 years ago
John drives a distance of 90 Km to the right at a steady speed of V1=25.00 m/s. Then he stops at the gas station for 10 minutes.
aleksley [76]

a. Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

b. t=6000\ s is the total time taken in the trip

c. d=126000\ m is the total distance

d. s=54000\ m towards right from the starting point.

e. v_a=21\ m.s^{-1}

f. \vec v_a=9\ m.s^{-1} towards right.

Explanation:

a.

Speed is a scalar quantity while velocity is a vector quantity.

Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

Speed is a directionless quantity while velocity constitutes direction.

b.

<em>Total time of round trip when we're given:</em>

  • distance travelled to the right, d_r=90000\ m
  • speed while travelling to the right, v_r=25\ m.s^{-1}
  • time spent at gas station, t_g=600\ s
  • time spent while travelling back towards the left, t_l=30\times 60=1800\ s
  • speed while travelling to the left, v_{_l}=20\ m.s^{-1}

<em>Now time taken for travelling towards right:</em>

t_r=\frac{d_r}{v_r}

t_r=\frac{90000}{25}

t_r=3600\ s

<u>Therefore total time taken in the round trip:</u>

t=t_r+t_l+t_g

t=3600+600+1800

t=6000\ s

c.

<em>Now, distance travelled towards left:</em>

d_l=v_{_l}\times t_l

d_l=20\times1800

d_l=36000\ m

<u>Therefore total distance:</u>

d=d_l+d_r

d=36000+90000

d=126000\ m

d.

Now, total displacement:

s=d_r-d_l

s=90000-36000

s=54000\ m towards right from the starting point.

e.

<u>Average speed:</u>

v_a=\frac{d}{t}

v_a=\frac{126000}{6000}

v_a=21\ m.s^{-1}

f.

<u>Average velocity:</u>

\vec v_a=\frac{s}{t}

\vec v_a=\frac{54000}{6000}

\vec v_a=9\ m.s^{-1} towards right.

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At the Olympics, high-diving competition,a diver from the top board curves her body in order to?
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