<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L
<u>Explanation:</u>
We are given:
Moles of carbon dioxide = 4.76 moles
<u>At STP:</u>
1 mole of a gas occupies a volume of 22.4 Liters
So, for 4.76 moles of carbon dioxide gas will occupy a volume of = 
Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L
Mr: 207.2
m=n×Mr= 6.53×207.2= 1353.02g
Answer: In order to increase the rate of reaction between hydrochloric acid and sugar increase the concentration of hydrochloric acid to 2 M because greater concentration results in more collision between the reactants.
Explanation:
More is the concentration of reactant molecules more will be the number of collisions between their molecules. As a result, more readily the products will be formed.
Hence, for the given reaction when concentration of HCl is increased then there will be increase in the number of collisions between reactants.
Thus, we can conclude that in order to increase the rate of reaction between hydrochloric acid and sugar increase the concentration of hydrochloric acid to 2 M because greater concentration results in more collision between the reactants.
Answer: The final pressure will decrease ad the value is 85 kPa
Explanation:
To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

where,
are the initial pressure and temperature of the gas.
are the final pressure and temperature of the gas.
We are given:

Putting values in above equation, we get:

Hence, the final pressure will decrease ad the value is 85 kPa
Answer: The amount of water produced is 9.3 grams
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g
mass of products = mass of carbon dioxide + mass of water = 48.9 g + mass of water
48.9 g + mass of water = 58.2 g
mass of water = 9.3 g