Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
Explanation:
Given: 
= 237 K, 
= 101.33 kPa, 
= ?
= 300 K, 
= 151.99 kPa, 
= 0.50 L
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
★ « <em><u>what is oxidation number of S in H2SO5??</u></em><em><u> </u></em><em><u>»</u></em><em><u> </u></em><em><u>★</u></em>
- <em><u>it's </u></em><em><u> </u></em><em><u>6</u></em><em><u>!</u></em><em><u>!</u></em>
Explanation:
- <em>Oxidation number of S in H2SO5 is 6 .</em>
Hey there!
Organic acid present in the methylene chloride when treated with aqueous NaOH it will be converted to aqueous soluble sodium carboxylate salt as shown below :
RCOOH (DCM layer) + NaOH ----------------> RCOONa (aqueous layer) + H₂O
the organic layer methylene chloride is immiscible with water, therefore it will present as two-layer, the large denser layer will present at the bottom
Density of dichloromethane = 1.325 g/mL
Density of water = 1 g/mL
Since dichloromethane density is more it will present at the bottom and water density is lesser, therefore, it will present its top, since RCOONa is aqueous soluble it present at the top aqueous layer
*Organic acid will present in the top layer
