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fomenos
4 years ago
13

Movement of solute from a 0.2% solute concentration solution to a 0.4% solute concentration solution is an example of

Chemistry
1 answer:
Lorico [155]4 years ago
6 0

Answer;

Active transport

Explanation;

Movement of solute from a 0.2% solute concentration solution to a 0.4% solute concentration solution is an example of active transport.

-Active transport is the process by which dissolved molecules move across a cell membrane from a lower to a higher concentration. In active transport, particles move against the concentration gradient - and therefore require an input of energy from the cell.

-During active transport, a protein pump uses energy, in the form of ATP, to move molecules from an area of low concentration to an area of high concentration.

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In every balanced chemical equation, each side of the equation has the same number of ____. select all that are true.
rjkz [21]
Hey..

It's answer should be atoms...
6 0
3 years ago
A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas
Anna71 [15]

Answer:

\large \boxed{\text{528.7 g} }

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"  

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:                      32.00

              2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol:                                                                  7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}

2. Mass of O₂

\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}

3 0
3 years ago
How many atoms of magnesium metal are needed to produce 3.87 moles of magnesium oxide
Ket [755]

Answer:

48.42g of Mg

Explanation:

4 0
3 years ago
Read 2 more answers
If an object has a volume of 2 millimeters and a mass of 10 grams, calculate the density of the object. (4 points)
kow [346]
Density = g/mL

10 g / 2 mL = 5 g/mL


3 0
4 years ago
What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?​
LekaFEV [45]

The volume of a sample of ammonia gas : 5.152 L

<h3>Further explanation</h3>

Given

0.23 moles of ammonia

Required

The volume of a sample

Solution

Assumed on STP

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So for 0.23 moles :

= 0.23 x 22.4 L

= 5.152 L

8 0
3 years ago
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