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docker41 [41]
3 years ago
9

Which set of symbols can be used to determine which calculations to perform first?

Computers and Technology
2 answers:
pogonyaev3 years ago
7 0

Answer:

your answer would be parentheses

Explanation:

just answered it on mine

hope this helps;)

-midnight-

Monica [59]3 years ago
5 0

Answer:

parentheses

Explanation: hope i helped <3 °ω°

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Create a SavingsAccount class. Use a static data member annualInterestRate to store the annual interest rate for each of the sav
andrew-mc [135]

Answer:

see explaination

Explanation:

SavingsAccount.h

#pragma once

#ifndef SAVINGS_H

#define SAVINGS_H

//SavingsAccount class declaration

class SavingsAccount

{

//declare data members

private:

//set annualInterestRate to 0.0 default value

static double annualInterestRate;

double savingsBalance;

public:

//set the balance

void setBalance(double);

//modify interest rates

static void modifyInterestRate(double);

//retruns total balance with interest

double calculateMonthInt();

};

#endif

SavingsAccount.cpp

//include required header files

#include<iostream>

#include"SavingsAccount.h"

using namespace std;

//set the annualInterestRate to 0

double SavingsAccount::annualInterestRate = 0;

//static funtion modify interest rate

void SavingsAccount::modifyInterestRate(double iRate)

{

annualInterestRate = iRate;

}

//set the balance

void SavingsAccount::setBalance(double bal)

{

savingsBalance = bal;

}

//calculating savings balance with monthly interest

double SavingsAccount::calculateMonthInt()

{

double monthInt = 0;

monthInt += savingsBalance*annualInterestRate / 12;

return savingsBalance += monthInt;

}

DriverProgram.cpp

//include required header files

#include<iostream>

#include "SavingsAccount.h"

using namespace std;

//main methods

int main()

{

//delcare class objects

SavingsAccount saver1, saver2;

//setter functions of balance

saver1.setBalance(2000.00);

saver2.setBalance(3000.00);

//Setting annual interset 0.03 to static variable

saver1.modifyInterestRate(0.03);

//finding the balance in saver1 and saver2 account

cout << "Balance of saver1 and saver2 on 3% interest Rate\n";

cout << "--------------------------------------------------\n";

cout << "Balance of saver1 = " << saver1.calculateMonthInt()

<< endl;

cout << "Balance of saver2 = " << saver2.calculateMonthInt()

<< endl << endl;

//Setting annual interset 0.04 to static variable

saver1.modifyInterestRate(0.04);

cout << "Balance of saver1 and saver2 on 4% interest Rate\n";

cout << "---------------------------------------------------\n";

cout << "New Balance of saver1 = " << saver1.calculateMonthInt() << endl;

cout << "New Balance of saver2 = " << saver2.calculateMonthInt() << endl<<endl;

return 0;

}

4 0
3 years ago
Answer this question for points lol
Zanzabum

Explanation:

jxjxnxnxnxkxozj nxkakthanksssssss lolll

8 0
2 years ago
Read 2 more answers
The question is inside the screenshot
Natalija [7]

Answer:

second choice

4 0
3 years ago
Write a C++ function for the following:
Nana76 [90]

Solution :

class Account

$ \{ $

public:

$\text{Account}()$;

double $\text{getBalance}$();

void $\text{setBalance}$();

$\text{bool withdraw}$(double bal);

$\text{private}:$

double $\text{balance}$;

}:

$\text{Account}()$ {}

double $\text{getBalance}$()

$ \{ $

$\text{return balance}$;

}

void $\text{setBalance}$(double $\text{balance}$)

$ \{ $

this.$\text{balance}$ = $\text{balance}$;

}

$\text{boolean}$ withdraw($\text{double bal}$)

$ \{ $

if($\text{balance}$ >= bal)

$ \{ $

$\text{balance}$ = $\text{balance}$ - bal;

$\text{return}$ true;

}

$\text{return}$ false;

}

}

4 0
2 years ago
Assume the user types in 7 and 10. What is output by the following?
Marianna [84]

Answer:

Enter a number: 7

Enter a number: 10

Traceback (most recent call last):

 File "main.py", line 3, in <module>

   print (numi + num2)

NameError: name 'numi' is not defined

Explanation:

The typo in the print statement causes a run-time error, where obviously num1+num2 was expected, and an output of 17.

3 0
3 years ago
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