The process of a chemical change is when it occur when a substance called chemical synthesis or alternatively chemical decomposition into two or more different substances
Answer:
it might be nitrogen. if not hen I'm sorry
Answer:
153.8 g/mol.
Explanation:
The molar mass of a compound = ∑ atomic masses of atoms.
<em>∴ The molar mass of CCl₄ = 1(atomic masss of C) + 4 (atomic mass of Cl) </em>= (12.0 g/mol) + 4 (35.45 g/mol) = <em>153.8 g/mol.</em>
It’s molecular shape.
When the two hydrogen atoms bond with the oxygen, they attach to the top of the molecule rather like Mickey Mouse ears. This molecular structure gives the water molecule polarity, or a lopsided electrical charge that attracts other atoms. The end of the molecule with the two hydrogen atoms is positively charged.
Answer:
Of the following equilibria, only one will shift to the right in response to a decrease in volume.
On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Decrease the volume
If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. So, the equilibrium will shift in the direction number of gaseous moles are less.
On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.
On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.
![2 SO_3 (g) \rightleftharpoons 2 SO_2 (g) + O_2 (g)](https://tex.z-dn.net/?f=2%20SO_3%20%28g%29%20%5Crightleftharpoons%202%20SO_2%20%28g%29%20%2B%20O_2%20%28g%29)
On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.
![H_2 (g) + Cl_2 (g) \rightleftharpoons 2 HCl (g)](https://tex.z-dn.net/?f=H_2%20%28g%29%20%2B%20Cl_2%20%28g%29%20%5Crightleftharpoons%202%20HCl%20%28g%29%20)
On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.
![2HI (g) \rightleftharpoons H_2 (g) + I_2 (g)](https://tex.z-dn.net/?f=2HI%20%28g%29%20%5Crightleftharpoons%20H_2%20%28g%29%20%2B%20I_2%20%28g%29)
On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.