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GalinKa [24]
3 years ago
15

Can a real heat engine cycle be more efficient than the Carnot heat engine efficiency?

Engineering
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

No

Explanation:

As we know that in practical engine there always present the friction between the two parts,always there present heat transfer due to finite temperature difference ,it means that the real engine can not be totally reversible engine.And on the other hand Carnot heat engine is a totally reversible heat engine.So we can say that a real heat engine efficiency is always less than Carnot engine.

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ANSWER ASAP<br> What is the point system?<br> this is for driving
lara31 [8.8K]

Answer:

A point system assigns point values to traffic violations for each state. When the DMV receives a conviction notice from the court, the offense is entered on your driving record and points are assigned. These points are counted during a specified time period.

Explanation:

3 0
3 years ago
melinda is using a rectangular brass bar in a sculpture she is creating. the brass bar has a length that is 4 more than 3 times
lawyer [7]

Answer:

180 x 60 inches

Width = 60 inches

Length = 180 inches

Explanation:

Given

Let L = Length

W = Width

P = Perimeter

Length = 3 * Width

L = 3W

Perimeter of Brass = 480 inches

P = 480

Perimeter is given as 2(L + W);

So, 2 (L + W) = 480

L + W = 480/2

L + W = 240

Substitute 3W for L; so,

3W + W = 240

4W = 240

W = 240/4

W = 60 inches

L = 3W

L = 3 * 60

L = 180 inches

6 0
3 years ago
Read 2 more answers
The fracture strength of glass may be increased by etching away a thin surface layer. It is believed that the etching may alter
Korvikt [17]

Answer:

the ratio of the etched to the original crack tip radius is 30.24

Explanation:

Given the data in the question;

we determine the initial fracture stress using the following expression;

(σf)₁ = 2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2 ----- let this be equation 1

where; (σ₀)₁ is the initial fracture strength

(p_t)₁ is the original crack tip radius

α₁ is the original crack length.

first, we determine the final crack length;

α₂ = α₁ - 16% of α₁

α₂ = α₁ - ( 0.16 × α₁)

α₂ = α₁ - 0.16α₁

α₂ = 0.84α₁

next, we calculate the final fracture stress;

the fracture strength is increased by a factor of 6;

(σ₀)₂ = 6( σ₀ )₁

Now, expression for the final fracture stress

(σf)₂ = 2(σ₀)₂ [ α₂/(p_t)₂ ]^{1/2 ------- let this be equation 2

where (p_t)₂ is the etched crack tip radius

value of fracture stress of glass is constant

Now, we substitute 2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2 from equation for (σf)₂  in equation 2.

0.84α₁ for α₂.

6( σ₀ )₁ for (σ₀)₂.

∴

2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2  = 2(6( σ₀ )₁) [ 0.84α₁/(p_t)₂ ]^{1/2  

divide both sides by 2(σ₀)₁

[ α₁/(p_t)₁ ]^{1/2  =  6 [ 0.84α₁/(p_t)₂ ]^{1/2

[ 1/(p_t)₁ ]^{1/2  =  6 [ 0.84/(p_t)₂ ]^{1/2

[ 1/(p_t)₁ ]  =  36 [ 0.84/(p_t)₂ ]

1 / (p_t)₁ = 30.24 / (p_t)₂

(p_t)₂ = 30.24(p_t)₁

(p_t)₂/(p_t)₁ = 30.24

Therefore, the ratio of the etched to the original crack tip radius is 30.24

6 0
3 years ago
How does the Freedom Tower at the World Trade Center demonstrate a function of architecture? (Select all that apply.)
alexandr402 [8]

Answer:

It tells a people's history.

It expresses a legacy.

Explanation:

The Freedom Tower is the most important building in the United States, both for its height (it is the tallest in the nation and the continent) and for its commercial importance and its historical significance (it is part of the One World Trade Center complex, which replaced to the Twin Towers after the 2001 attack).

Thus, this building expresses a legacy as it symbolizes America's recovery from the terrorist threat, as well as perseverance and strength in the face of adversity that America has as a nation. On the other hand, it tells a story, as it is located in the same place where the Twin Towers were, marking an indelible memory of what happened in that place.

7 0
3 years ago
A closed, rigid tank fitted with a paddle wheel contains 2.0 kg of air, initially at 200oC, 1 bar. During an interval of 10 minu
RUDIKE [14]

Answer:

T=833.8 °C

Explanation:

Given that

m= 2 kg

T₁=200 °C

time ,t= 10 min = 600 s

Work input = 1 KW

Work input = 1 x 600 KJ=600 KJ

Heat input = 0.5 KW

Q= 05 x 600 = 300 KJ

Gas is ideal gas.

We know that for ideal gas internal energy change given as

ΔU= m Cv ΔT

For air Cv= 0.71 KJ/kgK

From first law of thermodynamics

Q  = ΔU +W

Heat input taken as positive and work in put taken as negative.

300 KJ = - 600 KJ + ΔU

ΔU = 900 KJ

ΔU= m Cv ΔT

900 KJ = 2 x 0.71 x (T- 200 )

T=833.8 °C

So the final temperature is T=833.8 °C

8 0
3 years ago
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