Answer:
Cell wall and chloroplasts is correct option.
Explanation:
Hope it will help ^_^
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Cleavage lacks the growth phase of mitosis resulting in progressively smaller cells
Answer:
Ahmed and Fatima, two teenage siblings, are fighting over the evening newspaper. Knowing Ahmed only wants the sports section and Fatima only wants the latest stock quotations, their mother takes the paper and gives each the section containing their news of interest. In the context of mediation, the mother arrived at a(n) <u><em>integrative agreement.</em></u>
Explanation:
In business studies, an integrative agreement can be described as a situation in which all the parties benefit from an action and are in win-win situation. An integrative agreement tends to find beneficial options for both the parties at dispute so that a mutual agreement can occur between them.
In the following scenario, Ahmed and Fatima's mother provided a solution which benefited both of them. Hence, it is an example of an integrative agreement.
