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a school bus has stopped to allow children to get off the bus which graph shows the motion of the bus?

Usimov [2.4K]

Answer: what is it in

Explanation:

4 0

3 years ago

Five moles of an ideal monatomic gas with an initial temperature of 121 ∘C expand and, in the process, absorb an amount of heat

liq [111]

Answer:

T₂ ≈ 107.85∘C

Explanation:

The question didn't state if the volume is constant or not as such, we can apply the first law of thermodynamic

From the first law of thermodynamic,

ΔU = Q - W

where ΔU = Internal Energy, Q = Quantity of heat absorbed, W = Amount of work done.

Q = 1200 J and W = 2020 J

∴ ΔU = 1200 -2020 = -820 J.

Using the ideal gas equation,

ΔU = 3/2nRΔT...................................equation 1

where n = number of moles, R = Molar gas constant, ΔT = Change in temperature = (T₂ - T₁).

Modifying equation 1,

ΔU = 3/2nR(T₂ -T₁)...............................equation 2.

making T₂ the subject of the relation in equation 2,

T₂ = {2/3(ΔU)/nR}+T₁........................ equation 3

where T₁=121∘C, R= 8.314 J / mol, n=5 moles, ΔU=-820 J

Substituting these values into equation 3,

∴ T₂ ={ 2/3(-820)/(5×8.314)}+121

T₂ = {2×(-820)/ (3×5×8.314)}+121

T₂={-1640/124.71}+ 121

T₂ = {-13.151} + 121

∴T₂ = 121 - 13.151 = 107. 849∘C

T₂ ≈ 107.85∘C

3 0

3 years ago

A student wants to design an experiment to study the transformation of mechanical energy. Which object can be used to investigat

Vsevolod [243]

I guess it’s the 3rd one

7 0

3 years ago

Read 2 more answers

The magnitude of a vector can never be less than the magnitude of one of its components. Group of answer choices True False

pogonyaev

Answer:

True

Explanation:

As the formula for magnitude of a vector v and their components $v_1, v_2, v_3, v_4,..., v_n$ is

$v^2 = v_1^2 + v_2^2 + ... +v_n^2$

Since $v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2 \geq 0$ , this means the sum of them, $v^2$ , is always greater or equal to $v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2$

6 0

3 years ago

A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is

mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate = 150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

$h= \frac{1}{2}at^2$

$h= \frac{1}{2}4.71\times4.96^2$

h= 58.012 m

h≅ 58 m

4 0

3 years ago