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3 years ago

Put the following events in the order they occurred to lead to the formation of the solar system:

Physics

1 answer:

AfilCa [17]3 years ago

8 0

Answer:

Third → First → Second → Fourth

Explanation:

Initially helium and Hydrogen in abundance started to form atoms

Following the atoms formation by hydrogen and helium bombardment of new matter into the Earth took place.

The bombardment of matter resulted in separation of Earth into respective layers based on the weight of the matter.

A primitive ocean was created as a result of off gassing of the volcanoes.

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Give an example of a physical entity that is quantized. State specifically what the entity is and what the limits are on its val

Bogdan [553]

Answer:

A charge is a physical entity that has been quantized. The limits on its values are the value of a charged particle quantized in the state where 'n'...

Explanation:

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3 years ago

Read 2 more answers

In vacuum, red light travels at a greater speed than blue light does. <br> a. true <br> b. false?

3241004551 [841]

B)False.......they travels at the same speed

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3 years ago

A 0.20-kg particle moves along the x axis under the influence of a conservative force. The potential energy is given by

anastassius [24]

Answer:

e) 11 m/s

Explanation:

For a particle under the action of a conservative force, its mechanical energy at point 0 is must be equal to its mechanical energy at point 1:

$K_1+U_1=K_0+U_0\\\\\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(x_1)^2+(2.0\frac{J}{m^4})(x_1)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})(x_0)^2+(2.0\frac{J}{m^4})(x_0)^4]$

In $x_1=1.0m$ the speed is given, so $v_1=5.0\frac{m}{s}$ and $x_0=0$ . Replacing:

$\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(1m)^2+(2.0\frac{J}{m^4})(1m)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})0^2+(2.0\frac{J}{m^4})(0)^4]\\\frac{mv_1^2}{2}+8.0J+2.0J=\frac{mv_0^2}{2}\\\frac{mv_0^2}{2}=\frac{mv_1^2}{2}+10J\\v_0=\sqrt{\frac{2}{m}(\frac{mv_1^2}{2}+10J)}\\v_0=\sqrt{\frac{2}{0.2kg}(\frac{(0.2kg)(5\frac{m}{s})^2}{2}+10J)}\\v_0=11.18\frac{m}{s}$

7 0

3 years ago

A 0.100-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wa

Gennadij [26K]

Answer:

Change in momentum of the stone is 3.673 kg.m/s.

Explanation:

Given:

Mass of the ball on the horizontal the surface, m = 0.10 kg

Velocity of the ball with which it hits the stone, v = 20 m/s

According to the question it rebounds with 70% of the initial kinetic energy.

We have to find the change in momentum i.e Δp

Before that:

We have to calculate the rebound velocity with which the object rebounds.

Lets say that the rebound velocity be "v1" and KE remaining after the object rebounds be "KE1".

⇒ $KE_1=0.7\times \frac{mv^2}{2}$

⇒ $KE_1=0.7\times \frac{0.10\times (20)^2}{2}$

⇒ $KE_1=0.7\times \frac{0.10\times 400}{2}$

⇒ $KE_1=14$ Joules (J).

Rebound velocity "v1".

⇒ $KE_1=\frac{m(v_1)^2}{2}$

⇒ $v_1 = \sqrt{\frac{2KE_1}{m} }$

⇒ $v_1 = \sqrt{\frac{2\times 14}{0.10} }$

⇒ $v_1=16.73$

⇒ $v_1=-16.73$ m/s ...as it rebounds.

Change in momentum Δp.

⇒ $\triangle p= m\triangle v$

⇒ $\triangle p= 0.10\times (20-(-16.73)$

⇒ $\triangle p= 0.10\times (20+16.73)$

⇒ $\triangle p= 0.10\times (36.73)$

⇒ $\triangle p = 3.673$ Kg.m/s

The magnitude of the change in momentum of the stone is 3.673 kg.m/s.

5 0

3 years ago

a car accelerates from rest at 3 m / s^2 along a straight road. how far has the car travelled after 4 s

evablogger [386]

Answer:

24 m

Explanation:

The motion of the car is a uniformly accelerated motion (=at constant acceleration), therefore we can find the distance covered by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time elapsed

a is the acceleration

For the car in this problem:

u = 0, since the car starts from rest

$a=3 m/s^2$ is the acceleration

t = 4 s is the time elapsed

Therefore, the distance covered is:

$s=0+\frac{1}{2}(3)(4)^2=24 m$

4 0

3 years ago