Answer:
The heat gain of the room due to higher efficiency is 2.84 kW.
Explanation:
Given that,
Output power of shaft = 75 hp
Efficiency = 91%
High efficiency = 95.4%
We need to calculate the electric input given to motor
Using formula of efficiency
We need to calculate the electric input
For, heigh efficiency
The reduction of the heat gain of the room due to higher efficiency is
Put the value into the formula
Hence, The heat gain of the room due to higher efficiency is 2.84 kW.
<span>When designing an experiment a benefit of larger sample sizes would be more representative data. This larger sample size would lead to perfect result. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer comes to your help.</span>
The net force on particle q₃ is 6.2128125 N.
<h3>What is electrostatic force?</h3>
The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.
F = kq₁q₂/d²
where k = 9 x 10⁹ N.m²/C²
Given is the diagram in which each of the particles has a charge of -2.35 x 10⁻⁶ C. Particles q₁ and q₂ are separated by 0.100 m and particles q₂ and q₃ are separated by 0.100 m.
Force acting on q₃ due to q₁
F₃₁ = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1)²
F₃₁ = 4.97025 N(in right direction)
Force acting on q₃ due to q₂
F₃₂ = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1+0.1)²
F₃₂ = 1.2425 N (in right direction)
Net force acting on particle q₃ is
F₃ = F₃₁ +F₃₂
F₃ = 4.97025 N + 1.2425 N
F₃ = 6.2128125 N
Thus the net force on a charged particle is 6.2128125 N to the right.
Learn more about electrostatic force.
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Answer:
The difference between the cost of operating LED and incandescent bulb is $5.1
Explanation:
We are given the cost of electricity that is 12.75 cents per kWh. We want to find out the difference in the operating cost of an incandescent and LED bulb for a time period of 2,000 hours.
Since we are not given the rating of the incandescent bulb and LED bulb, we will assume their ratings.
For a light intensity of 250 Lumens;
The average rating of an LED bulb is approximately 5 Watts.
The average rating of an incandescent bulb is approximately 25 Watts.
Now lets find out the kWh of each bulb.
Energy = Power×Time
For LED bulb:
E = 5×2,000 = 10,000 Wh
Divide by 1000 to convert into kWh
E = 10,000/1000 = 10 kWh
Cost = 12.75×10 = 127.5 cents
Cost = $1.27
For Incandescent bulb:
E = 25×2,000 = 50,000 Wh
Divide by 1000 to convert into kWh
E = 50,000/1000 = 50 kWh
Cost = 12.75×50 = 637.5 cents
Cost = $6.37
Difference in Cost:
Difference = $6.37 - $1.27 = $5.1
Therefore, the difference between the cost of operating LED and incandescent bulb is $5.1.
