Please elaborate more on your question so I can help you
<u>Given that:</u>
Ball dropped from a bridge at the rate of 3 seconds
Determine the height of fall (S) = ?
As we know that, S = ut + 1/2 ×a.t²
u =initial velocity = 0
a= g =9.81 m/s (since free fall)
S = 0+ 1/2 × 9.81 × 3²
<em> S = 44.145 m</em>
<em>44.145 m far is the bridge from water</em>
density = mass/volume = 100kg/10ml = 10kg/ml
voluime = mass/density = 50g/2 g/ml = 25 ml
mass = density x volume = 2x55 = 110 kg
The answer is D. 32 m.
The simple equation that connects speed (v), time (t), and distance (d) can be expressed as:

⇒

It is given:

t = 10 s
d = ?
So: