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3 years ago

I really don’t get this one

Physics

1 answer:

worty [1.4K]3 years ago

4 0

Compounds are molecules with 2 or more elements

So the answer would be the third one

CO2;H2O

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1. Since sleep is so important, we might wonder why people so often fail to get a sufficient amount

ziro4ka [17]

Answer: 9/10

Explanation:

because it's really important and makes you energetic

8 0

3 years ago

What is an uncharged body? In physics (simple words)

andriy [413]

An uncharged body is a body that has equal magnitude of positive as well as negative charge on it. So as soon as some charged body is placed near it, the charged body induces negative charges on the uncharged body.

4 0

3 years ago

A block is sliding down an inclined plane that makes an angle of 65o with the horizontal. If the coefficient of kinetic friction

Nezavi [6.7K]

Answer:

8.2 m/s²

Explanation:

m = mass of the block

μ = Coefficient of kinetic friction = 0.17

$F_{n}$ = Normal force on the block by the ramp

$f_{k}$ = kinetic frictional force

Force equation perpendicular to ramp surface is given as

$F_{n} = mg Cos65$

Kinetic frictional force is given as

$f_{k} = \mu F_{n}$

$f_{k} = \mu mg Cos65$

Force equation parallel to ramp surface is given as

$mg Sin65 - f_{k} = ma$

$mg Sin65 - \mu mg Cos65 = ma$

$g Sin65 - \mu g Cos65 = a$

$(9.8) Sin65 - (0.17) (9.8) Cos65 = a$

$a = 8.2$ m/s²

4 0

4 years ago

A 0.23-f capacitor is desired. What area must the plates have if they are to be separated by a 3.8-mm air gap?

tia_tia [17]

The area of the plates must have is(A)= 9.91×10⁷ m²

<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>

To calculate the the value of a area of the plates of a capacitor, we are using the formula,

C= $\frac{\epsilon_0 A}{d}$

Or, A= $\frac{C\times d}{\epsilon_0}$

Here we are given,

C= The desired capacitance of a capacitor.

= 0.23F

d=distance of separation between the plates.

=3.8mm= 0.0038m.

$\epsilon_0$ = permittivity of the vacuum.

=8.854×10⁻¹²F/m

We have to calculate the area of the plates must have = A m².

Now we put the known values in the above equation, we can get

A= $\frac{C\times d}{\epsilon_0}$

Or, A= $\frac{0.23\times 0.0038}{8.854\times 10^{-12}}$

Or, A= 9.91×10⁷ m²

From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²

Learn more about Capacitor:

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2 years ago

Water droplets forming on the outside of a cold glass of water on a hot, summer day is a example of which part of the water cycl

sergiy2304 [10]

Answer:

Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.

Explanation:

4 0

3 years ago