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dalvyx [7]
3 years ago
5

Determine the wavelength of incident electromagnetic radiation required to cause an electron transition from the n = 5 to the n

= 7 level in a hydrogen atom.
Physics
1 answer:
ollegr [7]3 years ago
8 0
The correct answer is: wavelength = 4562 nm

Explanation:

Rydberg's formula is given as:
\frac{1}{\lambda} = R[ \frac{1}{n_1^2}  - \frac{1}{n_2^2} ] --- (1)

Where 
R = Rydberg's constant = 1.096 * 10^7 per meter
n_1 = 5
n_2 = 7

λ = Wavelength

Plug in the values in (1):

(1)=> \frac{1}{\lambda} = (1.096 * 10^7)[ \frac{1}{5^2} - \frac{1}{7^2} ]

\frac{1}{\lambda} = (1.096 * 10^7)[ 0.04 - 0.020 ] \\ \lambda =  \frac{1}{(1.096 * 10^7)[0.020 ]} \\ \lambda = 4562 nm
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Calculate the force on an object with mass of 50kg and gravity of 10​
GarryVolchara [31]
Answer: 500 N

Explanation:

The formula to find the force exerted by a mass, we may use F = mg, where g, the gravity, and a, the acceleration, can be interchangeable in the formula.

1) F = 50 x 10
2) F = 500 N

Hope this helps, brainliest would be appreciated :)
6 0
3 years ago
A rod of very small diameter with a mass 2m and length 3L is placed along the xaxis with one end at the origin. An identical rod
rewona [7]

Answer:

coordinates of the center of mass for these two rods

(x_{cm}, y_{cm})= (\frac{3L}{4},  \frac{3L}{4})cm

Explanation:

given

mass of a rod = 2m

length of the rod = 3L

mass of two rods = 2(2m) = 4m

radius = diameter/2 = \frac{3L}{2}

attached is the diagram and solution to the question

5 0
3 years ago
Birdman is flying horizontally at a
den301095 [7]

Answer:

68 m

Explanation:

Given that the horizontal velocity of the birdman = 17 m/s and

the height, h= 78 m.

The gravitational force is acting in the downward direction, so it will not change the horizontal speed.

The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.

Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, u_0=17 m/s.

In the vertical direction, u = 0,

The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e

s= 78 m

Let t be the time taken to cover a distance of 78 m.

Now, applying the equation of motion in the vertical direction,

s=ut+\frac 12 at^2

where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.

Here, a=g=9.81 m/s^2, so

78=0\times t +\frac 12 (9.81)t^2

\Rightarrow t^2=(78\times2)/9.81

\Rightarrow t = 4 seconds.

Hence, the time taken to reach the ground is 4 seconds.

As the horizontal speed, u_0=17 m/s, is constant throughout the journey, so

the horizontal distance covered by turd

= u\times t

= 17 \times 4 = 68 m.

So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly  above the start of the field.

Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.

5 0
3 years ago
You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that
kogti [31]

Answer:

111.5 m

Explanation:

Given that You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that your reaction time is 0.50 s and that your car brakes with constant acceleration. 

Use first equation of motion

V = U - at

Since the car is going to rest, V = 0 and a = negative

0 = 14 - a × 0.5

0.5a = 14

a = 14 /0.5

a = 28 m/s^2

Let us use second equation of motion

S = Ut - 1/2at^2

S = 14 × 0.5 - 0.5 × 28 × 0.5^2

S = 7 - 3.5

S = 3.5 m

115 - 3.5 = 111.5

Therefore, you are 111.5 metres from the intersection (in m) when you begin to apply the brakes.

6 0
3 years ago
Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
Reil [10]

Answer:

\Delta l=0.015m

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area A=0.5mm^2=0.5\times 10^{-6}m^2

Young's modulus \gamma=2\times 10^{11}Pa

Force F = 1500 N

So stress =\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa

We know that young's modulus =\frac{stress}{strain}

So 2\times 10^{11}=\frac{3\times 10^{9}}{strain}

strain=1.5\times 10^{-2}=0.015m

Now strain =\frac{\Delta l}{l}

0.015=\frac{\Delta l}{1}

\Delta l=0.015m

6 0
3 years ago
Read 2 more answers
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