I think the answer is C. Hope this helped.
Use Arrhenius equation:
k = A*exp(-Ea/RT)
We have:
1.35x10^2/s = A*exp(-85600/(8.314*298.15))
or: A = 1.342x10^17/s
It is a piece of cake to calculate:
k = 1.342x10^17*exp(-85600/(8.314*348.15))
= 1.92x10^4/s
A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
<h3>What is a decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
- Step 1: Write the balanced equation for the decomposition of KHCO₃.
2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)
The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.
- Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.
In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.
0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃
- Step 3: Calculate the mass percentage of KHCO₃ in the sample.
There are 1.25 g of KHCO₃ in the 1.775 g sample.
%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%
A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
Learn more about decomposition reactions here: brainly.com/question/14219426
The atomic number of an atom that has six protons, six neutrons, and six electrons is 6. And the element is carbon.
Carbon is known as a tetravalent compound.
It has four electrons in its outermost shell. It forms a covalent bond with other compounds.
The number of neutrons. = 6
Number of electrons = 6
Number of protons = 6
So the atomic number of the compound is,
The atomic number of an element = Number of protons present in its nucleus
The number of protons given in the compound is 6.
So the atomic number of the compound is also 6.
Carbon has six atomic numbers.
Therefore, the atomic number of an atom that has six protons, six neutrons, and six electrons is 6. And the element is carbon.
To know more about electrons, refer to the below link:
brainly.com/question/1255220
#SPJ4
