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garik1379 [7]
3 years ago
13

An organism’s genotype is

Chemistry
1 answer:
Mrac [35]3 years ago
5 0
It’s A trust me 92ww
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The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make
natta225 [31]

Answer:

the energy of the third excited rotational state \mathbf{E_3 = 16.041 \ meV}

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = \dfrac{m_1 \times m_2}{m_1 + m_2}

μ = \dfrac{1 \times 35}{1 + 35}

μ = \dfrac{35}{36}

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ  = \\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \  kg

μ  = 1.6139 × 10⁻²⁷ kg

r_o = 127 \ pm = 127*10^{-12} \ m

The rotational level Energy can be expressed by the equation:

E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)

where ;

J = 3 ( i.e third excited state)  &

I = \mu r^2_o

E_J= \dfrac{h^2}{8  \pi  \mu r^ 2 \mur_o } \times J ( J +1)

E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8  \times  \pi ^2  \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2  } \times 3 ( 3 +1)

E_3= 2.5665 \times 10^{-21} \ J

We know that :

1 J = \dfrac{1}{1.6 \times 10^{-19}}eV

E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV

E_3 = 16.041  \times 10 ^{-3} \ eV

\mathbf{E_3 = 16.041 \ meV}

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11. The back part of the cerebrum deals with hearing<br><br> True<br><br> False
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The answer is: True

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I am a celestial body that does not produce light. I orbit a planet
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A moon would be the correct answer.
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An atom of selenium (Se) forms a monatomic ion. Which of the following ions does it most likely form? Se2+ Se2 Se6+ Se6 *Not exp
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<span>I didn't know Selenium was considered organic? :P atoms form ions that mimic the electronic structure of noble gases. so add or subtract electrons from the atom to achieve the configuration of a noble gas.</span>
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A 23.9g object was submerged into 50.5ml of water. If the water rose to 89.4ml then what is the object's density?
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Answer:

50.2

Explanation:

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