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garik1379 [7]
3 years ago
13

An organism’s genotype is

Chemistry
1 answer:
Mrac [35]3 years ago
5 0
It’s A trust me 92ww
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You are working in the lab, how many grams of solute you need to make 200.0 g of 3.4% of solution?
Goryan [66]

Answer:

6.8g of solute are needed

Explanation:

Percent by mass, (w/w%) is defined as the mass of solute in 100g of solution. A solution that is 3.4% contains 3.4g of solute in 100g of solution. That means to make 200g of solution are required:

200g solution * (3.4g solute / 100g solution) = 6.8g of solute are needed

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3 years ago
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How many moles of H20 are produced from 6.4 moles of NaOH?
lord [1]

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5 0
2 years ago
Calculate the pH of 0.50M H2S
-BARSIC- [3]
I got that pH=3.65 using the fact that Ka=[H⁺][A⁻]/[HA] at equilibrium.  In the ice table, I stands for initial, C stands for change, and E stands for equilibrium.  

I hope this helps.  Let me know if anything is unclear.

5 0
3 years ago
Consider an amphoteric hydroxide, m(oh)2(s), where m is a generic metal. estimate the solubility of m(oh)2 in a solution buffere
Colt1911 [192]
Missing data in your question: (please check the attached photo)
from this balanced equation:
M(OH)2(s) ↔ M2+(aq) + 2OH-(aq) and when we have Ksp = 2x10^-16
∴Ksp = [M2+][OH]^2
2x10^-16 = [M2+][OH]^2
a) SO at PH = 7 
∴POH = 14-PH = 14- 7 = 7
when POH = -㏒[OH]
7= -㏒[OH]
∴[OH] = 1x10^-7 m by substitution with this value in the Ksp formula,
∴[M2+] =Ksp /[OH]^2
            = (2x10^-16)/(1x10^-7)^2
             = 0.02 M
b) at PH =10
when POH = 14- PH = 14-10 = 4 
when POH = -㏒[OH-]
            4  = -㏒[OH-]
∴[OH] = 1x10^-4 ,by substitution with this value in the Ksp formula
[M2+] = Ksp/ [OH]^2
          = 2x10^-16 / (1x10^-4)^2
          = 2x10^-8 M
c) at PH= 14 
when POH = 14-PH
                   = 14 - 14 
                   = 0
when POH = -㏒[OH]
              0 = - ㏒[OH]
∴[OH] = 1 m 
by substitution with this value in Ksp formula :
[M2+] = Ksp / [OH]^2
          = (2x10^-16) / 1^2
          = 2x10^-16 M


8 0
3 years ago
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