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lina2011 [118]
3 years ago
12

A large atom decays and emits a particle. After the reaction is complete, the atom’s mass has changed substantially. What kind o

f particle has most likely been emitted? a)alpha particle b)beta particle c)positron d)photon
Chemistry
2 answers:
hoa [83]3 years ago
5 0
The answer is alpha particles  <span />
Mrac [35]3 years ago
5 0
The correct answer is A) Alpha particle
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Fire extinguishers that spray carbon dioxide on the fire, work very effectively because it forms a blanket around the burning ma
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I think it will option B it will retain enough heat

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Write einstein's equation that explains the energy from nuclear reactions. _________ use the caret symbol (^) to show an exponen
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4 0
3 years ago
Read 2 more answers
The balanced chemical equation for the combustion of butane is: 2C2H2 + 5O2 CO2 + 2H2O 2CH4 + 5O2 2CO2 + 4H2O 2C4H10 + 13O2 8CO2
SCORPION-xisa [38]
Butane is C₄H₁₀.

C_4H_{10} + O_2 \to CO_2 + H_2O \\ \\&#10;\hbox{balance carbon and hydrogen on the right-hand side:} \\&#10;C_4 H_{10} + O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\&#10;\hbox{balance oxygen on the left-hand side:} \\&#10;C_4 H_{10} + \frac{13}{2} \ O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\&#10;\hbox{multiply by 2 to get rid of the fraction:} \\&#10;2 \ C_4H_{10} + 13 \ O_2 \to 8 \ CO_2 + 10 \ H_2O

The balanced equation is 2 C₄H₁₀ + 13 O₂ <span>→</span> 8 CO₂ + 10 H₂O.
3 0
3 years ago
The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?
Agata [3.3K]

<u>Answer:</u> The molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

PbI_2\rightleftharpoons Pb^{2+}+2I^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Pb^{2+}][I^-]^2

We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L

Hence, the molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

3 0
3 years ago
Particals in the nucleus of an atom are its _________ and ____________.
Illusion [34]
That would be Protons and Neutrons.
6 0
2 years ago
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