(a) The net flux through the coil is zero.
In fact, the magnetic field generated by the wire forms concentric circles around the wire. The wire is placed along the diameter of the coil, so we can imagine as it divides the coil into two emisphere. Therefore, the magnetic field of the wire is perpendicular to the plane of the coil, but the direction of the field is opposite in the two emispheres. Since the two emispheres have same area, then the magnetic fluxes in the two emispheres are equal but opposite in sign, and so they cancel out when summing them together to find the net flux.
(b) If the wire passes through the center of the coil but it is perpendicular to the plane of the wire, the net flux through the coil is still zero.
In fact, the magnetic field generated by the wire forms concentric lines around the wire, so it is parallel to the plane of the coil. But the flux is equal to

where

is the angle between the direction of the magnetic field and the perpendicular to the plane of the coil, so in this case

and so the cosine is zero, therefore the net flux is zero.
Answer:
I belive it would be ture
Explanation:
It's been a while since I learned this but I think that is right.
Solid and liquids are much more denser than gas because their molecules are close to each other and with that the molecules of them can't move that freely unlike the gas molecules. Also, because of being near to each other the molecules of solid and liquids became heavy making them dense.
Answer:
0.015 m/s2
Explanation:
Using Newtons 2nd law.
F = ma where F = Force applied, m = mass of the object and a = acceleration acquired.
So substitute the values in SI units.
m =
kg
Therefore F = 0.003×5 = 0.015 m/s2
Answer:
The electric potential will be "259.695 volt".
Explanation:
In the given question, the figure is not provided. Below is the attached figure given.
Given:





Now,
At point P, the electric potential will be:
⇒ 
By putting values, we get
⇒ ![=9\times 10^9 [\frac{6.39\times 10^{-9}}{0.40} +\frac{3.22\times 10^{-9}}{0.25} ]](https://tex.z-dn.net/?f=%3D9%5Ctimes%2010%5E9%20%5B%5Cfrac%7B6.39%5Ctimes%2010%5E%7B-9%7D%7D%7B0.40%7D%20%2B%5Cfrac%7B3.22%5Ctimes%2010%5E%7B-9%7D%7D%7B0.25%7D%20%5D)
⇒ 